LintCode 156: Merge Interval 题目描述 给出若干闭合区间,合并所有重叠的部分. 样例 给出的区间列表 => 合并后的区间列表: [ [ [1, 3], [1, 6], [2, 6], => [8, 10], [8, 10], [15, 18] [15, 18] ] ] Fri Feb 24 2017 思路 首先将区间们按照开始元素的大小排序,然后从头到尾遍历一遍,若遇到该区间的开始元素小于前一个区间的结束元素时,将两个区间合并. 区间合并可以直接修改前一个区间的结束…

Merge Interval: Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 算法分析:首先要对给定序列排序.然后再去遍历合并. class Interval { int start; int end; Interval() { start = 0; end = 0…

56. Merge Interval 0. 参考文献 序号 文献 1 花花酱 LeetCode 56. Merge Intervals 2 [LeetCode] Merge Intervals 合并区间 1. 题目 Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]…

lc57 Insert Interval 仔细分析题目,发现我们只需要处理那些与插入interval重叠的interval即可,换句话说,那些end早于插入start以及start晚于插入end的interval都可以保留.我们只需要两个指针,i&j分别保存重叠interval中最早start和最晚end即可,然后将interval [i, j]插入即可 class Solution { public int[][] insert(int[][] intervals, int[] newInte…

Description Given a collection of intervals, merge all overlapping intervals. Example Given intervals => merged intervals: [ [ (1, 3), (1, 6), (2, 6), => (8, 10), (8, 10), (15, 18) (15, 18) ] ] Challenge O(n log n) time and O(1) extra space. 题意:给定一个…

题目: Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 题解: 这道题主要难点是改写Comparator. Comparator接口定义了两个方法:compare( )和equals( ).这里给出的compare( )方法按顺序比较了两个元素: int comp…

Interval的合并时比较常见的一类题目,网上的Amazon面经上也有面试这道题的记录.这里以LeetCode上的例题做练习. Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an inter…

Given a collection of intervals, merge all overlapping intervals.   Example Given intervals => merged intervals: [ [ [1, 3], [1, 6], [2, 6], => [8, 10], [8, 10], [15, 18] [15, 18] ] ] Challenge O(n log n) time and O(1) extra space. 解法一: /** * Defini…

Merge Intervals 2014.2.26 21:28 Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. Solution: The problem didn't guarantee that the set of intervals is sorted, so…

［抄题］: 给出若干闭合区间,合并所有重叠的部分. 给出的区间列表 => 合并后的区间列表: [ [ [1, 3], [1, 6], [2, 6], => [8, 10], [8, 10], [15, 18] [15, 18] ] ] [暴力解法]: 时间分析: 空间分析: ［思维问题］: ［一句话思路］: 区间类问题,先把起点排序才能具有逐个合并的能力和性质 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: lambda…