1106. Lowest Price in Supply Chain (25) A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from supplier to customer. Starting from one root supplier, everyone on the chain buy…

本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90444872 1106 Lowest Price in Supply Chain (25 分)   A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from su…

A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from supplier to customer. Starting from one root supplier, everyone on the chain buys products from one's supplier in a pric…

https://pintia.cn/problem-sets/994805342720868352/problems/994805362341822464 A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from supplier to customer. Starting from one ro…

A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)-- everyone involved in moving a product from supplier to customer. Starting from one root supplier, everyone on the chain buys products from one's supplier in a pric…

题目 A supply chain is a network of retailers(零售商), distributors(经销商), and suppliers(供应商)– everyone involved in moving a product from supplier to customer. Starting from one root supplier, everyone on the chain buys products from one's supplier in a pr…

简单dfs #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; +; vector<int>g[maxn]; int n; double P,r…

题意:略 思路:寻找树的叶结点中深度最低的,记录最低深度minDepth和具有相同最低深度的结点个数cnt. 代码: #include <cstdio> #include <cmath> #include <vector> using namespace std; ; vector<int> tree[maxn]; ,cnt=; void dfs(int v,int depth) { ){ if(depth<minDepth){ cnt=; minDe…

求叶子结点处能活得最低价格以及能提供最低价格的叶子结点的个数 #include<bits/stdc++.h> using namespace std; ; vector<int>vec[N]; int minn=0x3f3f3f3f; ; void dfs(int v,int step) { ){ if(minn>step){ minn=step; num=; } else if(minn==step){ num++; } } ;i<vec[v].size();i++)…

统计树的最小层数以及位于该层数上的叶子节点个数即可. 代码里建树我用了邻接链表的存储方式——链式前向星,不了解的可以参考,非常好用: http://www.cnblogs.com/chenxiwenruo/p/4513754.html #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> using names…