109. Convert Sorted List to Binary Search Tree (List; Divide-and-Conquer, dfs)

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108. Convert Sorted Array to Binary Search Tree 109. Convert Sorted List to Binary Search Tree -- 将有序数组或有序链表转成平衡二叉排序树

108. Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *ri…

leetcode 108. Convert Sorted Array to Binary Search Tree 、109. Convert Sorted List to Binary Search Tree

108. Convert Sorted Array to Binary Search Tree 这个题使用二分查找,主要要注意边界条件. 如果left > right,就返回NULL.每次更新的时候是mid-1,mid+1. 自己推一下基本就可以验证了. class Solution { public: TreeNode* sortedArrayToBST(vector<int>& nums) { ,nums.size() - ); } TreeNode* ToBST(vecto…

【LeetCode】109. Convert Sorted List to Binary Search Tree 解题报告（Python）

[LeetCode]109. Convert Sorted List to Binary Search Tree 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/convert-sorted-list-to-binary-search-tree/description/ 题目描述: Given a s…

Leetcode#109 Convert Sorted List to Binary Search Tree

原题地址跟Convert Sorted Array to Binary Search Tree(参见这篇文章)类似,只不过用list就不能随机访问了. 代码: TreeNode *buildBST(ListNode *head, int len) { ) return NULL; ListNode *p = head; ; < len) { p = p->next; leftLen++; } TreeNode *node = new TreeNode(p->val); node->…

【一天一道LeetCode】#109. Convert Sorted List to Binary Search Tree

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博欢迎转载,转载请注明出处 (一)题目 Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. (二)解题本题大意:给定一个单向链表,构造出平衡二叉搜索树解题思路:参考[一天一道Leet…

[LeetCode] 109. Convert Sorted List to Binary Search Tree 把有序链表转成二叉搜索树

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never diffe…

leetcode 109 Convert Sorted List to Binary Search Tree ----- java

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 和上一题类似,把数组换成链表,所以可以两种做法: 1.把链表换成数组,然后用上一题的方法,这样会比较慢. 2.每次找到中间的点,作为节点,然后递归,其实原理还是二分查找. /** * Definition for singly-linked list. * public…

109. Convert Sorted List to Binary Search Tree

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. ============== 题目:将升序的链表,转化为BST(note:此BST要求是高度平衡,就是树种左右子树高度差不超过1) 思路: def TreeNode* sortedListToBST(ListNode* head){ 按照slow/fast方式找到链表的中间节点m…

【Leetcode】109. Convert Sorted List to Binary Search Tree

Question: Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node n…

109. Convert Sorted List to Binary Search Tree (List; Divide-and-Conquer, dfs)

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */…