题目链接 很好的一道题,用了三天多的时间,终于知道了我为什么T的原因,也知道了在Splay的同时该怎样子的节约时间,因为Splay本身就是大常数的O(N*logN),我们如果不在各种细节上节约时间,很容易就会造成T的是因为我们制造了一个同样的大常数. 先讲解一下题意:有两种操作,一个是一段区间内的值翻转,另一个是讲[a, b]裁剪下来,然后将这段区间贴到剩下的元素的第c位后面. 然后讲一下Splay翻转的几个要点,还有就是可能的T的点,我们要做到的翻转的操作自然不是太过于难想,很多人都能想到的就…

Play with Chain Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6779    Accepted Submission(s): 2678 Problem Description YaoYao is fond of playing his chains. He has a chain containing n diamond…

给定两种操作,一种是把一个数列的某一段切下来插到剩余数列的某一个位置上. 一种是翻转操作,把数列的某一段进行翻转. 都是Splay的基本操作.标准的Rotateto调整出 [a,b]区间.然后对[a,b]区间修改parent标记和child标记.然后记住PushUp把修改标记推到树根上.简单一点就直接对某个节点spaly(x,0)就OK! 1: #include <cstdio> 2: #include <iostream> 3: #include <vector> 4…

题目大意 给一个数列,初始时为 1, 2, 3, ..., n,现在有两种共 m 个操作 操作1. CUT a b c 表示把数列中第 a 个到第 b 个从原数列中删除得到一个新数列,并将它添加到新数列中第 c 个数的后面 操作2. FLIP a b 表示把数列中第 a 个数到第 b 个数翻转 经过 m 个操作之后,输出这个数列 1≤n, m≤3*100000 做法分析 这题也不好用线段树做,用 Splay 很快就搞出来了 对于"操作1. CUT a b c" ,只需要将 a-1 旋转…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3487 YaoYao is fond of playing his chains. He has a chain containing n diamonds on it. Diamonds are numbered from 1 to n.At first, the diamonds on the chain is a sequence: 1, 2, 3, …, n.He will perform t…

Queue-jumpers Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3139    Accepted Submission(s): 848 Problem Description Ponyo and Garfield are waiting outside the box-office for their favorite mo…

Looploop Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1651    Accepted Submission(s): 517 Problem Description XXX gets a new toy named Looploop. The toy has N elements arranged in a loop, an…

http://acm.hdu.edu.cn/showproblem.php?pid=3487 题意:有两种操作:1.Flip l r ,把 l 到 r 这段区间 reverse.2.Cut a b c ,把 a 到 b 这段区间切掉,再把这段区间接到切掉后的第 c 个数的后面. 思路:做完了上一道变态题目,做这道题目如鱼得水.Cut的时候就是把a 到 b 放到keytree的位置,记录一下当前keytree的值,然后切掉,再把切掉后的第 c 个数转到 root 的位置,再把这个记录的值重新连接回…

Play with Chain Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) [Problem Description] YaoYao is fond of playing his chains. He has a chain containing n diamonds on it. Diamonds are numbered from 1 to n. At first, t…

Play with Chain Time Limit: 6000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2783    Accepted Submission(s): 1141 Problem Description YaoYao is fond of playing his chains. He has a chain containing n diamond…