报错信息: ERROR Dispatcher:38 - Exception occurred during processing request: user is not mapped [from user where username = ?]; nested exception is org.hibernate.hql.ast.QuerySyntaxException: user is not mapped [from user where username = ?]org.springfr…
java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: t_aty_disease is not mapped [SELECT new com.upup.app.doctor.symptom.entity.Symptom(d.id) FROM t_aty_disease d,t_aty_symptom s where d.id = s.id] at org.hibernate.ejb.Abst…
转自:https://www.cnblogs.com/albert1017/archive/2012/08/25/2656873.html org.hibernate.hql.ast.QuerySyntaxException: tb_voteoption is not mapped [from tb_voteoption where voteID=?] 解决方案:这一般是HQL语句错误 因为Hibernate是对类查询的 ,而不是对数据库表进行查询例如:return getHibernateTe…
非常诡异的报错,信息如下:org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped [select count(*) from User u where u.userName=? and u.userPassword=? ]Caused by: org.hibernate.hql.internal.ast.QuerySyntaxException: User is not mapped类似的报错信息的解决方法,…
异常情况: 最近在把一个项目拆分多个 module 的时候数据库查询遇到这个异常:org.hibernate.hql.internal.ast.QuerySyntaxException: Identification is not mapped JPA 查询方法如下: public Identification findIdentificationByWxId(String wxId) { JPAQueryBase query = new JPAQuery(entityManager).from…
继承映射中查询对象的过程中报错: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: person is not mapped [FROM person] HQL查询的是持久化类名而不是表名, List<Person> persons=session.createQuery("FROM person").list(); 所以应该改为from Per…
Spring 5.0 +Jpa,使用@Query实现 自定义查询报错: java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: student is not mapped [select id,name,createtime,sex,age from student s] 原因是查询语句中 from 后面写的是实体类名,而不是表名.…
