Median String time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You are given two strings ss and tt, both consisting of exactly kk lowercase Latin letters, ss is lexicographically less than …

Codeforce 1144 E. Median String 解析(思維.大數運算) 今天我們來看看CF1144E 題目連結 題目 給你兩個長度為\(k\)的字串\(s\)和\(t\),求字典序排序的,\(s,t\)的中位字串. 前言 想法 觀察一下,發現我們可以把字串看成26進位的數字,所以我們只要計算\((s+t)/2\)就好. 程式碼: const int _n=2e5+10; int tt,k,inc,z,left; char s[_n],t[_n],res[_n]; main(voi…

You are given two strings ss and tt, both consisting of exactly kk lowercase Latin letters, ss is lexicographically less than tt. Let's consider list of all strings consisting of exactly kk lowercase Latin letters, lexicographically not less than ss …

把字符串看作是26进制的数,从后往前翻译,那么就可以把两个串变成对应的26进制的数字,那么只要把两个数加起来除以二就得到中间的串对应的数了,同理再转化回来就行了.但是这样会有一个问题就是串的长度有2e5,26的2e5次方显然不可求,所以需要对每一位进行手动的加和运算.对于两个串,我们假设a串从后往前的每一位对应的数值为a0, a1, a2...,b串从后往前的每一位对应的数值为b0, b1, b2...对于进制加法,有 扔一下垃圾代码: #include <iostream> #include…

原题链接:https://codeforces.com/problemset/problem/1144/E tag:字符串模拟,大整数. 题意:给定两个字符串,求字典序中间串. 思路:可以把这个题当做一个26进制数的模拟.a~z分别代表0~25,然后求平均,在通过数字反求字符串. 然后写出这么个代码 #include<bits/stdc++.h> using namespace std; typedef unsigned long long ll; ll _input(ll); void _o…

题意:给你两个字符串\(s\)和\(t\),保证\(t\)的字典序大于\(s\),求他们字典序中间的字符串. 题解:我们假设题目给的不是字符串,而是两个10禁止的正整数,那么输出他们之间的数只要把他两加起来除\(2\)就行了,那么对于字符串又为何不可呢?我们可以将每个字母看成\(26\)进制的数,像高精度那样模拟加法运算的过程,然后再模拟除\(2\)的过程即可. 代码: int k; string s,t; int c[N]; int d[N]; int main() { ios::sync_w…

http://codeforces.com/contest/1144 A. Diverse Strings A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", &qu…

A - Diverse Strings CodeForces - 1144A A string is called diverse if it contains consecutive (adjacent) letters of the Latin alphabet and each letter occurs exactly once. For example, the following strings are diverse: "fced", "xyz", &…

B. Rebranding The name of one small but proud corporation consists of n lowercase English letters. The Corporation has decided to try rebranding — an active marketing strategy, that includes a set of measures to change either the brand (both for the…

Google面试题 股市上一个股票的价格从开市开始是不停的变化的,需要开发一个系统,给定一个股票,它能实时显示从开市到当前时间的这个股票的价格的中位数(中值). SOLUTION 1: 1.维持两个heap,一个是最小堆,一个是最大堆. 2.一直使maxHeap的size大于minHeap. 3. 当两边size相同时,比较新插入的value,如果它大于minHeap的最大值,把它插入到minHeap.并且把minHeap的最小值移动到maxHeap. ...具体看代码 /***********…