Question 806. Number of Lines To Write String Solution 思路:注意一点,如果a长度为4,当前行已经用了98个单元,要另起一行. Java实现: public int[] numberOfLines(int[] widths, String S) { int left = 0; int lines = 0; for (char c : S.toCharArray()) { left += widths[c - 'a']; if (left >=…

806. Number of Lines To Write String 整体思路: 先得到一个res = {a : 80 , b : 10, c : 20.....的key-value对象}(目的是当调用res["a"]时得到一个等于10的值): 遍历传入的字符串,把每个元素带入到res中,并把所有的值进行累加:得到一个累加值sum,如:sum= sum + res["a"] + res["b"] + res["c"]...…

problem 806. Number of Lines To Write String solution: class Solution { public: vector<int> numberOfLines(vector<int>& widths, string S) { , len = ; for(auto ch:S) { int t = widths[ch-'a']; ) line++; len = (len+t>) ? t : len+t; } return…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 使用ASIIC码求长度 使用字典保存长度 日期 题目地址:https://leetcode.com/problems/number-of-lines-to-write-string/description/ 题目描述 We are to write the letters of a given string S, from left to right…

题目要求 We are to write the letters of a given string S, from left to right into lines. Each line has maximum width 100 units, and if writing a letter would cause the width of the line to exceed 100 units, it is written on the next line. We are given an…

We are to write the letters of a given string S, from left to right into lines. Each line has maximum width 100 units, and if writing a letter would cause the width of the line to exceed 100 units, it is written on the next line. We are given an arra…

解答 class Solution { public: vector<int> numberOfLines(vector<int>& widths, string S) { vector<int> result; int line=1,units=0; map<char,int> pairs; char c='a'; for(int width:widths){ pairs.insert(make_pair(c,width)); ++c; } for…

这是悦乐书的第319次更新,第340篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第188题(顺位题号是806).我们要将给定字符串S的字母从左到右写成行.每行最大宽度为100个单位,如果写一个字母会导致该行的宽度超过100个单位,则会写入下一行.给出一个数组宽度,一个数组,其中widths[0]是'a'的宽度,widths[1]是'b'的宽度,widths[25]是'z'的宽度. 现在回答两个问题:S中至少有一个字符有多少行,最后一行使用的宽度是多少?将答案作为长…

We are to write the letters of a given string S, from left to right into lines. Each line has maximum width 100 units, and if writing a letter would cause the width of the line to exceed 100 units, it is written on the next line. We are given an arra…

1.题目描述 2.分析 使用一个map将字母和数字对应起来,方便后续使用. 3.代码 vector<int> numberOfLines(vector<int>& widths, string S) { map<char,int> m; vector<int> ans; ; i< ;i++) m[i+'a'] = widths[i]; ; ; ; ; t < S.size(); t++) { curLen += m[ S[t] ]; la…

We are to write the letters of a given string S, from left to right into lines. Each line has maximum width 100 units, and if writing a letter would cause the width of the line to exceed 100 units, it is written on the next line. We are given an arra…

我们要把给定的字符串 S 从左到右写到每一行上,每一行的最大宽度为100个单位,如果我们在写某个字母的时候会使这行超过了100 个单位,那么我们应该把这个字母写到下一行.我们给定了一个数组 widths ,这个数组 widths[0] 代表 'a' 需要的单位, widths[1] 代表 'b' 需要的单位,..., widths[25] 代表 'z' 需要的单位. 现在回答两个问题:至少多少行能放下S,以及最后一行使用的宽度是多少个单位?将你的答案作为长度为2的整数列表返回. 示例 1: 输入…

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" Output:…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 统计 正则表达式 字符串分割 日期 题目地址:https://leetcode.com/problems/number-of-segments-in-a-string/#/description 题目描述 Count the number of segments in a string, where a segment is defined to b…

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" Output:…

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" Output:…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3941 访问. 统计字符串中的单词个数,这里的单词指的是连续的不是空格的字符. 请注意,你可以假定字符串里不包括任何不可打印的字符. 输入: "Hello, my name is John" 输出: 5 Count the number of segments in a string, where a segment is defined to be a…

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" Output:…

434. Number of Segments in a String Easy Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Inp…

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. For example, Input: "Hello, my name is John" Output: 5 public int countSegments(String s) { String trimmed = s.trim(); if (…

原题: 434. Number of Segments in a String 解题: 刚看到题目时,觉得可以通过统计空格个数,但想想有可能会有多个空格的情况 思路: 一:遍历字符,if条件碰到非空格时,计数加1,然后while循环跳过非空格字符,一直到最后 二:设置flag初始为0,当碰到非空格时,计数加1,且flag置1,当flag为1且碰到空格时,flag再重置为0 思路一是自己想的,思路二更巧妙,是论坛里摘抄的 AC代码: 思路一: class Solution { public: in…

［抄题］: Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printable characters. Example: Input: "Hello, my name is John" O…

Count the number of segments in a string, where a segment is defined to be a contiguous sequence of non-space characters. Please note that the string does not contain any non-printablecharacters. Example: Input: "Hello, my name is John" Output:…

一.报错截图 [Vue warn]: Invalid prop: type check failed for prop "jingzinum". Expected Number with value NaN, got String with value "fuNum". 二.报错代码 <!DOCTYPE html> <html lang="en"> <head> <meta charset="U…

这是悦乐书的第226次更新,第239篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第93题(顺位题号是434).计算字符串中的段数,其中段定义为非空格字符的连续序列.请注意,该字符串不包含任何不可打印的字符.例如: 输入:"Hello, my name is John" 输出:5 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,使用Java语言编写和测试. 02 第一种解法 使用正则表达式,将其拆分成字符串数组…

1.题目描述 2.题目分析 找到字符串中的空格即可 3.代码 int countSegments(string s) { ){ ; } vector<string> v; ; i < s.size(); i++){ if( isspace(s[i]) ){ continue; } ; while( !isspace(s[j]) ){ if( j < s.size() ) j++; else break; } string sb = s.substr(i,j-i); v.push_b…

题目: Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively. Below is one possible representation of s1 = "great": great / \ gr eat / \ / \ g r e at / \ a t To scramble the string, we ma…

原题链接: http://oj.leetcode.com/problems/scramble-string/  这道题看起来是比較复杂的,假设用brute force,每次做分割,然后递归求解,是一个非多项式的复杂度,一般来说这不是面试官想要的答案. 这事实上是一道三维动态规划的题目,我们提出维护量res[i][j][n],当中i是s1的起始字符,j是s2的起始字符,而n是当前的字符串长度,res[i][j][len]表示的是以i和j分别为s1和s2起点的长度为len的字符串是不是互为scram…

题目描述: We are to write the letters of a given string S, from left to right into lines. Each line has maximum width 100 units, and if writing a letter would cause the width of the line to exceed 100 units, it is written on the next line. We are given a…

统计字符串中的单词个数,这里的单词指的是连续的非空字符.请注意,你可以假定字符串里不包括任何不可打印的字符.示例:输入: "Hello, my name is John"输出: 5 详见:https://leetcode.com/problems/number-of-segments-in-a-string/description/ C++: 方法一: class Solution { public: int countSegments(string s) { int cnt=0; f…