Java [Leetcode 100]Same Tree】的更多相关文章

题目描述: Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 解题思路: 递归调用比较左子树和右子树以及该节点. 代码描述: /** * Definition for a binar…
100. Same Tree Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical and the nodes have the same value. Example 1: Input: 1 1 / \ / \ 2 3 2 3 [1,2,3]…
100. Same Tree class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { if(p == NULL && q == NULL) return true; else if(p == NULL || q == NULL) return false; if(p->val != q->val) return false; return isSameTree(p->left,q->l…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 判断两棵树是否相同. 很简单.递归. /** * Definition for a binary tree node. * publ…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 解题思路: JAVA实现如下: public boolean isSameTree(TreeNode p, TreeNode q)…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value.  题目标题:Tree 这道题目给了我们两个二叉树,让我们判断这两个二叉树是否一摸一样.利用preOrder 来遍历tree, 对于每…
Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical and the nodes have the same value. Example 1: Input: 1 1 / \ / \ 2 3 2 3 [1,2,3], [1,2,3] Outpu…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 给出两个二叉树,写一个方法判断两个二叉树是否相等, 如果两个二叉树相等,说明结构相同并且每个节点的值相同. 如果两个节点都为空,则说…
题目描述: Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. 解题思路: 使用栈.从根节点开始迭代循环访问,将节点入栈,并循环将左子树入栈.如果当前节点为空,则弹出栈顶节点,也就是当前节点的父节点,并将父节点的值加入到list中,然后选择右节点作为循环的节点,依次循环.…
题目描述: Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,2,3]. 解题思路: 这个问题最简单的方法是使用递归,但是题目规定不能使用,得使用迭代的方法. 那么我们考虑使用栈来实现. 思路是每次遍历这节点,把该点的值放入list中,然后把该点的右孩子放入栈中,并将当前点设置为左…