445-Add Two Numbers II You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the…

SGU 108 Self-numbers 2 Problem's Link Mean: 略有这样一种数字:对于任意正整数n,定义d(n)为n加上n的各个位上的数字(d是数字的意思,Kaprekar发明的一个术语).如:d(75) = 75 + 7 + 5 = 87.给定任意正整数n,你可以构建出无限的整数递增:n, d(n), d(d(n)), d(d(d(n))), ……举个例子,你从33开始,那么下一个数就是33 + 3 + 3 = 39, 再下一个就是39 + 3 + 9 = 51, 接着…

Cubic-free numbers II Time Limit: 10000ms Memory Limit: 131072KB This problem will be judged on HUST. Original ID: 121464-bit integer IO format: %lld      Java class name: Main   A positive integer n is called cubic-free, if it can't be written in th…

You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not con…

445. 两数相加 II 445. Add Two Numbers II 题目描述 给定两个非空链表来代表两个非负整数.数字最高位位于链表开始位置.它们的每个节点只存储单个数字.将这两数相加会返回一个新的链表. 你可以假设除了数字 0 之外,这两个数字都不会以零开头. 进阶: 如果输入链表不能修改该如何处理?换句话说,你不能对列表中的节点进行翻转. LeetCode445. Add Two Numbers II中等 示例: 输入: (7 -> 2 -> 4 -> 3) + (5 ->…

Question 445. Add Two Numbers II Solution 题目大意:两个列表相加 思路:构造两个栈,两个列表的数依次入栈,再出栈的时候计算其和作为返回链表的一个节点 Java实现: public ListNode addTwoNumbers(ListNode l1, ListNode l2) { Stack<Integer> s1 = new Stack<>(); Stack<Integer> s2 = new Stack<>();…

这道题难在 hash 上, 求出答案很简单, 关键是我们如何标记, 由于 某个数变换后最多比原数多63 所以我们只需开一个63的bool数组就可以了! 同时注意一下, 可能会有相同的询问. 我为了防止给的询问不是有序的,还排了一边序. #include <cstdio> #include <cstring> #include <cstdlib> #include <iostream> #include <algorithm> #include &…

You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not con…

原题链接在这里:https://leetcode.com/problems/add-two-numbers-ii/ 题目: You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return…

You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not con…

翻译:引自 http://www.cnblogs.com/yylogo/archive/2011/06/09/SGU-108.html 在1949年印度的数学假D.R. Kaprekar发现了一种叫做self-number的经典数字,对于任意正整数n,定义d(n)为n加上n的各个位上的数字(d是数字的意思,Kaprekar发明的一个术语).如:d(75) = 75 + 7 + 5 = 87.给定任意正整数n,你可以构建出无限的整数递增:n, d(n), d(d(n)), d(d(d(n))),…

[题目描述] You have two numbers represented by a linked list, where each node contains a single digit. The digits are stored in forward order, such that the 1's digit is at the head of the list. Write a function that adds the two numbers and returns the…

You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

1. 原始题目 You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two…

［抄题］: You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two n…

You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

题目描述: 解题思路: 给定两个链表(代表两个非负数),数字的各位以正序存储,将两个代表数字的链表想加获得一个新的链表(代表两数之和). 如(7->2->4->3)(7243) + (5->6->4)(564) = (7->8->0->7)(7807) 此题与[LeetCode2]Add Two Numbers解决思路类似,不同之处在于此题的数字以正序存储,故需要借助栈. Java代码: import java.util.Stack; //public cl…

You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…

You have two numbers represented by a linked list, where each node contains a single digit. The digits are stored in forward order, such that the 1's digit is at the head of the list. Write a function that adds the two numbers and returns the sum as…

题目标签:Linked List 题目给了我们两个 数字的linked list,让我们把它们相加,返回一个新的linked list. 因为题目要求不能 reverse,可以把 两个list 的数字都 存入 两个stack.利用了stack的特性,就可以从后面把数字相加,具体看code. Java Solution: Runtime:  6 ms, faster than 51.06% Memory Usage: 45.4 MB, less than 64.71% 完成日期:07/08/201…

""" You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume t…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 先求和再构成列表 使用栈保存节点数字 类似题目 日期 题目地址:https://leetcode.com/problems/add-two-numbers-ii/description/ 题目描述 You are given two non-empty linked lists representing two non-negative intege…

非常烦人的题,思路比较简单,十分容易出错,细节非常重要. 从四个不同的行走方向讨论经过的每一个格子. code: #include <iostream> #include <utility> #include <cmath> using namespace std; #define lb long double #define fi first #define se second pair<int , int > a, b; int n, tot; cons…

时间限制:0.5s 空间限制:6M 题意:         在b(2<b<36)进制中,找到所有长度为n(0<n<2000)的自守数k,满足k^2%b^n=k,字典序输出.         如 十进制中     9376^2 = 87909376   后面4位数都是9376. Solution:                可以发现长度为n的满足要求的数中,其后n-1位也是自守数.                这样的数是很稀疏的,可以直接从n=1的情况开始搜索.当找到长度为n的…

题意:这样的数有几个? 模仿筛法就能解出,但是内存不够.这就需要重复利用数组,用100大小的数组,所有的数对100取模.对于一个数,比如71,就在arr[78]=71记录下来.到78时,检查78-71<90.说明近期有数能产生78.而178对100取模也是78,如果后来(比178小90以内的数)没有数能产生78.那么178-arr[178]将>90就是符合条件的.而比178小90以内的数只能产生178,不可能产生78或者278. #include <iostream> #inclu…

1.题目描述 2.分析 首先将链表翻转,然后做加法. 最后将结果链表翻转. 3.代码 ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode* L1 = reverseList( l1 ); ListNode* L2 = reverseList( l2 ); ListNode* head = ); ListNode* result = head; ListNode* p1 = L1; ListNode* p2 = L2; ;…

给定两个非空链表来代表两个非负整数.数字最高位位于链表开始位置.它们的每个节点只存储单个数字.将这两数相加会返回一个新的链表.你可以假设除了数字 0 之外,这两个数字都不会以零开头.进阶:如果输入链表不能修改该如何处理?换句话说,你不能对列表中的节点进行翻转.示例:输入: (7 -> 2 -> 4 -> 3) + (5 -> 6 -> 4)输出: 7 -> 8 -> 0 -> 7详见:https://leetcode.com/problems/add-two…

题意:两个非空链表求和,这两个链表所表示的数字没有前导零,要求不能修改原链表,如反转链表. 分析:用stack分别存两个链表的数字,然后从低位开始边求和边重新构造链表. Input: (7 -> 2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 8 -> 0 -> 7 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListN…