Cut the Cake Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 263    Accepted Submission(s): 113 Problem Description MMM got a big big big cake, and invited all her M friends to eat the cake toge…

Cut the Cake Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 300    Accepted Submission(s): 135 Problem Description MMM got a big big big cake, and invited all her M friends to eat the cake toge…

Cut the Cake Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1657    Accepted Submission(s): 806 Problem Description MMM got a big big big cake, and invited all her M friends to eat the cake tog…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4762 题目大意:将n个草莓随机放在蛋糕上,草莓被看做是点,然后将蛋糕平均切成m份,求所有草莓在同一块蛋糕上的概率 Sample Input 2 3 3 3 4   Sample Output 1/3 4/27 分析:计算出这个概率公式为:n/(mn-1),m.n最大为20,mn超出了64位,用到大数,用java容易写出 代码如下: import java.math.BigInteger; impor…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4762 题目大意:一个圆形蛋糕,现在要分成M个相同的扇形,有n个草莓,求n个草莓都在同一个扇形上的概率. 算法思路:n个草莓在圆形上有一个最左边的,为了好理解,先把假设草莓有1-n的不同编号.  现在从n个草莓中选出一个编号A的放在最左边(这个最左边可以随便放),得到C(n,1)*1.然后把其余的n-1草莓不分先后的放在A的右边角大小为(360)/m的扇形区域内就可以了. 所以概率为 n/(m^(n-…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4762 题意:有个蛋糕,切成m块,将n个草莓放在上面,问所有的草莓放在同一块蛋糕上面的概率是多少.2 < M, N <= 20 分析:概率题,公式题.可惜我数学太差,想了好久都想不出来,看了题解还是不太明白怎么算的. 最后的概率公式为:n / (m^(n-1)),然后用高精度就可以了,最后的结果要约分,可以在计算的过程中求gcd(n,m),然后分子分母同除以该数就可以了. 这里有两个方法可以推出来.…

猜公式: ans=n/m^(n-1) #include<stdio.h> #include<string.h> struct BigNum { ]; int len; }; int gcd(int a,int b) { ) return a; return gcd(b,a%b); } BigNum mul(BigNum &a,int b) { BigNum c; int i,len; len=a.len; memset(c.num,,sizeof(c.num)); ) {…

Cut the cake Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1250    Accepted Submission(s): 489 Problem Description: Mark bought a huge cake, because his friend ray_sun’s birthday is coming. Ma…

题意很简单就不说了. 解题的关键就是这个公式 answer=n/(m^(n-1)); 要用到大数的乘法.然后java水过. import java.util.*; import java.math.*; public class Main { public static BigInteger gcd (BigInteger a, BigInteger b) { if (a.mod(b).equals(BigInteger.valueOf(0))) return b; return gcd(b,…

http://acm.hdu.edu.cn/showproblem.php?pid=2134 Problem Description Ice cream took a bronze medal in the Beijing match. Liu sir is very very happy. So he buys a cake for them. kiki is a child who likes eating, so the task of cuting cake was given to k…