链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=151 For each list of words, output a line with each word reversed without changing the order of the words. This problem contains multiple test cases! The first line of a multiple input is…
题目连接: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=1151 题目描述: For each list of words, output a line with each word reversed without changing the order of the words. This problem contains multiple test cases! The first line of a multip…
这道题相似 Word Break 推断能否把字符串拆分为字典里的单词 @LeetCode 只不过要求计算的并不不过能否拆分,而是要求出全部的拆分方案. 因此用递归. 可是直接递归做会超时,原因是LeetCode里有几个非常长可是无法拆分的情况.所以就先跑一遍Word Break,先推断能否拆分.然后再进行拆分. 递归思路就是,逐一尝试字典里的每个单词,看看哪一个单词和S的开头部分匹配,假设匹配则递归处理S的除了开头部分,直到S为空.说明能够匹配. Given a string s and a…
Word Reversal Time Limit: 2 Seconds Memory Limit:65536 KB For each list of words, output a line with each word reversed without changing the order of the words. This problem contains multiple test cases! The first line of a multiple input is an…
Given a string s and a list of strings dict, you need to add a closed pair of bold tag <b> and </b> to wrap the substrings in s that exist in dict. If two such substrings overlap, you need to wrap them together by only one pair of closed bold…
103. 反转单词 时间限制 1000 ms 内存限制 65536 KB 题目描述 给出一句英文句子(只由大小写字母和空格组成,不含标点符号,也不会出现连续的空格),请将其中的所有单词顺序翻转 输入格式 多组数据,以EOF结束. 每行一句英文句子(确保只由大小写字母和空格组成,不含标点符号,也不会出现连续的空格,字符串总长度1000以内) 输出格式 每组数据输出一行,为反转后的字符串 输入样例 It is a apple 输出样例 apple a is It eof: 在window下时是ctr…
String 字符串相加 对比 public static void main(String[] args) { String a = "helloword"; final String b = "hello"; String d = "hello"; String c = b + "word"; String e = d + "word"; String f ="hello"+&quo…
题目: Given two words (beginWord and endWord), and a dictionary's word list, find all shortest transformation sequence(s) from beginWord to endWord, such that: Only one letter can be changed at a time Each transformed word must exist in the word list.…
1.3 Given two strings, write a method to decide if one is a permutation of the other. 这道题给定我们两个字符串,让我们判断一个是否为另一个的全排列字符串.在LeetCode中,关于排列的题有如下几道,Permutation Sequence 序列排序,Permutations 全排列, Permutations II 全排列之二 和 Next Permutation 下一个排列.这道题跟它们比起来,算是很简单的…
String字符串相加的问题 前几天同事跟我说我之前写的代码中在操作字符串时候,使用字符串相加的方式而不是使用StringBuffer或者StringBuilder导致内存开销很大.这个问题一直在困扰我,因为在<Think in java>一书中,作者说使用"+"拼接字符串并不比StringBuffer或者StringBuilder效率低下,因为"+"是java唯一一个系统级的针对字符串的重载过的操作符. 大家都知道String是一个final修饰的类.…