这是一道在leetcode上看到的题目 一开始,我能想到的思路是蛮力法: 就遍历每个字符,然后对每个字符都尝试从1到n的长度,看有没有回文串,并记录以该字符起始的回文串的最大长度.这个思路其实没有上手实现,因为和前面的那题求最大没有重复字符的substring的原始思路一样,时间复杂度是O(n^3),是超时的. 然后是可以通过的方法: 两边扩展法: 抓住,回文串是轴对称的这个特点,即一个中心往两边探索,两边都是相等的.实现上先要遍历每个字符,从0序号到s.length()-2序号,这里的遍历,是…

5. Longest Palindromic Substring Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example: Input: "babad" Output: "bab" Note: "aba" is also a valid answer. Ex…

Markdown版本笔记 我的GitHub首页 我的博客 我的微信 我的邮箱 MyAndroidBlogs baiqiantao baiqiantao bqt20094 baiqiantao@sina.com 领扣-5 最长回文子串 Longest Palindromic Substring MD 目录 目录最长回文子串 Longest Palindromic Substring问题暴力循环法(最基础的方式)暴力循环法1暴力循环法2动态规划法(主流方式)技巧性型方法中心扩展算法(逻辑清晰)最长公…

Leetcode 5. Longest Palindromic Substring(最长回文子串, Manacher算法) Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Example 1: Input: "babad" Output: "bab" Note: "aba&q…

题目描述 Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 即给定一个字符串,求它的最长回文子串的长度(或者最长回文子串). 解法一 对于一个问题,一定可以找到一个傻的可爱的暴力解法,本题的暴力解法即…

题目来自 https://leetcode.com/problems/longest-palindromic-substring/ 题目:Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 给一个字符串…

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 这道题让我们求最长回文子串,首先说下什么是回文串,就是正读反读都一样的字符串,比如 "bob", "level", &q…

问题: Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 官方难度: Medium 翻译: 给定一个字符串S,找出最长回文子串,你可以假定字符串的最大长度为1000,并且只有一个最长回文子串. 例子:…

Given a string S, find the longest palindromic substring in S. You may assume that the maximum length of S is 1000, and there exists one unique longest palindromic substring. 题目的意思:输入一个字符串S,找出其最长回文串 用动态规划求解 决策变量:dp[i][j]记录从s[i]到s[j]组成的子串是否为回文. dp[i+1…

Given a , and there exists one unique longest palindromic substring. https://leetcode.com/problems/longest-palindromic-substring/ 求最大回文的长度,其实这道题比上一道有意思. 方法1 循环查询 (该方案为O(N*N*N)) public static boolean isPalindrome(String s, int start, int end) { if (((…