7.Reverse Integer Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only stor…

我现在在做一个叫<leetbook>的开源书项目,把解题思路都同步更新到github上了,需要的同学可以去看看 书的地址:https://hk029.gitbooks.io/leetbook/ 007. Reverse Integer[E]——处理溢出的技巧 题目 Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 思路 这题完全没丝毫的难度,任何人几分钟都可以写…

7. Reverse Integer 题目描述: Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note: Assume we are dealing with an environment which could o…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the integer's…

题目要求:将给出的整数进行逆序输出 注意:整数的最大范围-2147483648-2147483647,当翻转后的数超出范围后返回0 思路:对给出的整数除以10,取余和取整:然后对取整部分继续取余和取整,同时将前一次取余的部分乘10再加上该次取余...直至余数为零 public class Solution { public static void main(String[] args) { Solution sol = new Solution(); // System.out.println(…

13.Roman to Integer Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is writ…

一天一道LeetCode系列 (一)题目 Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 (二)解题 这题看上去很简单,动笔一挥之下,写出如下代码: class Solution { public: int reverse(int x) { bool flag = false; if(x<0) { x=-k; flag = true; } long result…

这是悦乐书的第143次更新,第145篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第2题(顺位题号是7),给定32位有符号整数,然后将其反转输出.例如: 输入: 123 输出: 321 输入: -123 输出: -321 输入: 120 输出: 21 给定反转整数范围: [−2^31, 2^31 − 1],即在int的最小值.最大值之间,如果反转整数超过此范围,则返回0. 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,…

这题简单,也花了我好长时间,我自己写的code比较麻烦,也没啥技巧:按正负性分类执行,先转化成字符串,用stringbuilder进行旋转,如果超出范围了就用try catch public int reverse(int x) { try { int result = 0; if (x == 0) { return x; } else if (x < 0) { String num = Integer.toString(0 - x); String newNum = new StringBui…

题目: Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only hold integers with…