1840: Jack Straws  Time Limit(Common/Java):1000MS/10000MS     Memory Limit:65536KByteTotal Submit: 154            Accepted:119 Description In the game of Jack Straws, a number of plastic or wooden "straws" are dumped on the table and players try…
Jack Straws Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 2911   Accepted: 1322 Description In the game of Jack Straws, a number of plastic or wooden "straws" are dumped on the table and players try to remove them one-by-one witho…
Jack Straws In the game of Jack Straws, a number of plastic or wooden "straws" are dumped on the table and players try to remove them one-by-one without disturbing the other straws. Here, we are only concerned with if various pairs of straws are…
Pick-up sticks Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1872    Accepted Submission(s): 706 Problem Description Stan has n sticks of various length. He throws them one at a time on the fl…
You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6837 Accepted Submission(s): 3303 Problem Description Many geometry(几何)problems were designed in the ACM/ICPC. A…
You can Solve a Geometry Problem too Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6425    Accepted Submission(s): 3099 Problem Description Many geometry(几何)problems were designed in the ACM/I…
题意:要求相交的线段都要塞进同一个集合里 sol:并查集+判断线段相交即可.n很小所以n^2就可以水过 #include <iostream> #include <cmath> #include <cstring> #include <cstdio> using namespace std; ]; char ch; int tmp,n; double X1,X2,Y1,Y2; #define eps 1e-8 #define PI acos(-1.0)//3…
描述 In the game of Jack Straws, a number of plastic or wooden "straws" are dumped on the table and players try to remove them one-by-one without disturbing the other straws. Here, we are only concerned with if various pairs of straws are connecte…
转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud Jack Straws Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 3512   Accepted: 1601 Description In the game of Jack Straws, a number of plastic or wooden "straws" are dumped o…
题意: 给出一系列线段,判断某两个线段是否连通. 思路: 根据线段相交情况建立并查集, 在同一并查集中则连通. (第一反应是强连通分量...实际上只要判断共存即可, 具体的方向啊是没有关系的..) 并查集合并的时候是根节点合并. 快速排斥试验不是必需的, 大规模数据可能是个优化吧. 跨立试验注意共线的情况. 共线判断注意与y 轴平行的情况. #include <cstdio> #include <cstring> #include <cmath> using names…