给定两个字符串 s 和 t,它们只包含小写字母.字符串 t 由字符串 s 随机重排,然后在随机位置添加一个字母.请找出在 t 中被添加的字母.示例:输入:s = "abcd"t = "abcde"输出:e解释:'e' 是那个被添加的字母.详见:https://leetcode.com/problems/find-the-difference/description/ C++: 方法一: class Solution { public: char findTheDif…

［抄题］: Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = &q…

原题 Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

题目要求 Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. 题目分析及思路 给定两个只由小写字母组成的字符串s和t,其中t是在s字符串组成…

1.题目大意 Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = &…

异或 找不同 —.— public class Solution { public char findTheDifference(String s, String t) { char temp = 0x00; for(int i = 0;i < s.length();i++){ temp =(char) (temp ^ s.charAt(i)); } for(int i = 0;i < t.length();i++){ temp =(char) (temp ^ t.charAt(i)); }…

给定两个字符串 s 和 t,它们只包含小写字母. 字符串 t 由字符串 s 随机重排,然后在随机位置添加一个字母. 请找出在 t 中被添加的字母. 示例: 输入: s = "abcd" t = "abcde" 输出: e 解释: 'e' 是那个被添加的字母. class Solution { public: char findTheDifference(string s, string t) { int sum = 0; int sum2 = 0; for(int…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:字典统计次数 方法二:异或 方法三:排序 日期 [LeetCode] https://leetcode.com/problems/find-the-difference/ Difficulty: Easy 题目描述 Given two strings s and t which consist of only lowercase letter…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

-------------------------------------------------- 先计算每个字母的出现次数然后减去,最后剩下的那一个就是后来添加的了. AC代码: public class Solution { public char findTheDifference(String s, String t) { int book[]=new int[26]; for(int i=0;i<s.length();i++) book[s.charAt(i)-'a']++; for…

一开始没看见shuffle...觉得同时遍历不就完事了.. 和那个所有数字出现2,有一个出现3次还是什么的一样,CHAR可以完美和INT相互切换. public class Solution { public char findTheDifference(String s, String t) { int res = 0; for(int i = 0; i < s.length();i++) { res ^= s.charAt(i); } for(int i = 0; i < t.length…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

题目: Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = &quo…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

最近做的题记录下. 258. Add Digits Given a non-negative integer num, repeatedly add all its digits until the result has only one digit. For example: Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it. int addDigi…

Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input: s = "abcd" t = "ab…

389. Find the Difference Easy Given two strings s and t which consist of only lowercase letters. String t is generated by random shuffling string s and then add one more letter at a random position. Find the letter that was added in t. Example: Input…

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

刷题备忘录,for bug-free leetcode 396. Rotate Function 题意: Given an array of integers A and let n to be its length. Assume Bk to be an array obtained by rotating the array A k positions clock-wise, we define a "rotation function" F on A as follow: F(k…

1. Two Sum https://leetcode.com/problems/two-sum/description/ 不使用额外空间需要n*n的复杂度 class Solution { public: vector<int> twoSum(vector<int>& nums, int target) { ;i<nums.size()-;i++){ ;j<nums.size();j++){ if(nums[i] + nums[j] == target){ v…

刷题备忘录,for bug-free 招行面试题--求无序数组最长连续序列的长度,这里连续指的是值连续--间隔为1,并不是数值的位置连续 问题: 给出一个未排序的整数数组,找出最长的连续元素序列的长度. 如: 给出[100, 4, 200, 1, 3, 2], 最长的连续元素序列是[1, 2, 3, 4].返回它的长度:4. 你的算法必须有O(n)的时间复杂度 . 解法: 初始思路 要找连续的元素,第一反应一般是先把数组排序.但悲剧的是题目中明确要求了O(n)的时间复杂度,要做一次排序,是不能达…

算法思想 二分查找 贪心思想 双指针 排序 快速选择 堆排序 桶排序 搜索 BFS DFS Backtracking 分治 动态规划 分割整数 矩阵路径 斐波那契数列 最长递增子序列 最长公共子系列 0-1 背包 数组区间 字符串编辑 其它问题 数学 素数 最大公约数 进制转换 阶乘 字符串加法减法 相遇问题 多数投票问题 其它 数据结构相关 栈和队列 哈希表 字符串 数组与矩阵 1-n 分布 有序矩阵 链表 树 递归 层次遍历 前中后序遍历 BST Trie 图 位运算 参考资料 算法思想 二…

源代码地址:https://github.com/hopebo/hopelee 语言:C++ 301. Remove Invalid Parentheses Remove the minimum number of invalid parentheses in order to make the input string valid. Return all possible results. Note: The input string may contain letters other tha…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

自从上个月进入实验室的云安全项目组后,因为要接触到实际的代码,在实验室博士的建议下我们项目组的硕士开始刷LeetCode练习编程能力,保持每周抽空刷几道算法题.虽然刷的不多,到现在一共只刷了不到30题,但在刷题的过程中还是有很多感触的. 实验室的博士建议我们按照题目的难易顺序循序渐进由易到难来刷,我也就照做了.因为前段时间在系统地学Python语言,所以我主要用的是Python语言来做,有的题目也采用了C/C++.Java甚至C#多种语言来尝试.在刷题的过程中,总结了自己的一些问题: 1. 对于…

299. Bulls and Cows 思路:抽屉法,放进secrets,拿出guess,最终cows = cows - bulls public String getHint(String secret, String guess) { int bulls = 0; int cows = 0; int[] numbers = new int[10]; for(int i = 0; i < secret.length(); i++){ if(secret.charAt(i) == guess.c…

Python 位操作: 按位与 &, 按位或 | 体会不到 按位异或 ^ num ^ num = 0 左移 << num << 1 == num * 2**1 右移 >> num >> 2 == num / 2**2 取反 ~ ~num == -(num + 1) 1. Single Number Given an array of integers, every element appears twice except for one. Find…