Description FJ's N (1 <= N <= 10,000) cows conveniently indexed 1..N are standing in a line. Each cow has a positive integer height (which is a bit of secret). You are told only the height H (1 <= H <= 1,000,000) of the tallest cow along with…
题目 1635: [Usaco2007 Jan]Tallest Cow 最高的牛 Time Limit: 5 Sec  Memory Limit: 64 MB Description FJ's N (1 <= N <= 10,000) cows conveniently indexed 1..N are standing in a line. Each cow has a positive integer height (which is a bit of secret). You are t…
s[i]为差分后的"i这头牛前有几头比它高",计算答案的时候加成前缀和,假设第一头最高减一下即可 用map记录一下被加过的区间,避免重复 #include<iostream> #include<cstdio> #include<map> #include<algorithm> using namespace std; const int N=10005; int n,q,h,r,s[N],f[N],a,b; map<int,bool…
1635: [Usaco2007 Jan]Tallest Cow 最高的牛 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 383  Solved: 211[Submit][Status] Description FJ's N (1 <= N <= 10,000) cows conveniently indexed 1..N are standing in a line. Each cow has a positive integer height…
http://www.lydsy.com/JudgeOnline/problem.php?id=1635 差分序列是个好东西啊....很多地方都用了啊,,, 线性的进行区间操作orz 有题可知 h[a+1]~a[b-1]都是比h[a]和h[b]小,那么最佳方案就是将次区间的所有高度-1,那么我们就将整个区间-1 也就是sum[a+1]--, sum[b]++ 而条件h[a]>=h[b]我还不明觉厉啊..... (脑补:假设一般情况下h[a]==h[b]的,而却有c使得(a, c), pos[c]…
[题意]n头牛,其中最高h.给定r组关系a和b,要求满足h[b]>=h[a]且a.b之间都小于min(h[a],h[b]),求第i头牛可能的最高高度. [算法]差分 [题解]容易发现r组关系只能包含或不相交. 先假设所有牛是最高高度. 对于一组关系(a,b)显然只需要让区间[a+1,b-1]整体-1就好了.使用差分维护. 特别判断a=b和a=b+1和多区间LR一样的情况. #include<cstdio> #include<algorithm> #include<cst…
1635: [Usaco2007 Jan]Tallest Cow 最高的牛 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 346  Solved: 184[Submit][Status] Description FJ's N (1 <= N <= 10,000) cows conveniently indexed 1..N are standing in a line. Each cow has a positive integer height…
[Usaco2007 Jan]Cow School牛学校 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 175  Solved: 83[Submit][Status][Discuss] Description Bessy 正在上学并且分数还不错. 她考了N (一个数据中1 <= N <= 50,000, 其余数据 1 <= N <= 50,00) 次试,每次考试得分为T_i, 满分为P_i(0 <= T_i <= P_i &…
1636: [Usaco2007 Jan]Balanced Lineup Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 772  Solved: 560线段树裸题... Description For the daily milking, Farmer John's N cows (1 <= N <= 50,000) always line up in the same order. One day Farmer John decides to o…
考虑相邻的两头奶牛 a , b , 我们发现它们顺序交换并不会影响到其他的 , 所以我们可以直接按照这个进行排序 --------------------------------------------------------------------------------- #include<cstdio> #include<cstring> #include<algorithm> #include<iostream>   #define rep( i ,…