ZOJ1081 Points Within】的更多相关文章

ZOJ1081 给一个点和一个多边形 判断点在多边形内(边上)还是在多边形外 在多边形外的点引一条射线必然穿过多边形的两条边 而在多边形内的点则不一定. 当然凹多边形有特殊情况 但是总能找到对应位置关系的边来抵消 #include<iostream> #include<stdio.h> #include<stdlib.h> #include<string.h> #include<math.h> #include<algorithm>…
嘟嘟嘟 题面:给一个\(n\)个点的多边形和\(m\)个点,判断每一个点是否在多边形内. 解法:射线法. 就是从这个点引一条射线,如果与多边形有奇数个交点,则在多边形内部. 那么只用枚举每一条边,然后判断这条边与射线有无交点.为了方便,射线为水平的.然后可以用叉积判断三点共线,以及多边形的两个端点纵坐标的大小关系. 但要注意一些特殊情况,比如有一个交点是多边形的顶点,所以为了避免重复统计,需要规定交在每一条边的下断点还是上端点. #include<cstdio> #include<ios…
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=1081 题目大意:给定一个点数为 n 的多边形,点按照顺序给出,再给出 m 个点,询问每个点是否在多边形内. —————————————————————————————— 计算几何开荒期,所以都算是板子吧……既然是板子那么题解自然也都是集网上之大成. 所以以后也就不多说了.正式往下看题解吧. —————————————————————————————— 这是一道求点是否在一…
每一个实数都能用有理数去逼近到任意精确的程度,这就是有理数的稠密性.The rational points are dense on the number axis.…
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 这道题给了我们一堆二维点,然后让我们求最大的共线点的个数,根据初中数学我们知道,两点确定一条直线,而且可以写成y = ax + b的形式,所有共线的点都满足这个公式.所以这些给定点两两之间都可以算一个斜率,每个斜率代表一条直线,对每一条直线,带入所有的点看是否共线并计算个数,这是整体的思路.但是还有…
题目链接 Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 分析:首先要注意的是,输入数组中可能有重复的点.由于两点确定一条直线,一个很直观的解法是计算每两个点形成的直线,然后把相同的直线合并,最后包含点最多的直线上点的个数就是本题的解.我们知道表示一条直线可以用斜率和y截距两个浮点数(垂直于x轴的直线斜率为无穷大,截距用x截距),同时还需要保存每…
Find the K closest points to a target point in a 2D plane. class Point { public int x; public int y; public Point(int x, int y) { this.x = x; this.y = y; } } class Solution { public List<Point> findKClosest(Point[] points, int k, Point p) { // max h…
Max Points on a Line 题目描述: Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 解题思路: 1.首先由这么一个O(n^3)的方法,也就是算出每条线的方程(n^2),然后判断有多少点在每条线上(N).这个方法肯定是可行的,只是复杂度太高2.然后想到一个O(N)的,对每一个点,分别计算这个点和其他所有点构成的斜率,具有相同斜率最…
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 思路 关键是浮点数做key不靠谱,struct hash以及 int calcGCD(int a, int b)的写法 代码 /** * Definition for a point. * struct Point { * int x; * int y; * Point() : x(0), y(0)…
Max Points on a Line Submission Details 27 / 27 test cases passed. Status: Accepted Runtime: 472 ms Submitted: 0 minutes ago Submitted Code Language: java   Edit Code         /** * Definition for a point. * class Point { * int x; * int y; * Point() {…
Problem Introduction The goal in this problem is given a set of segments on a line and a set of points on a line, to count, for each point, the number of segments which contain it. Problem Description Task.In this problem you are given a set of point…
Problem Introduction You are given a set of segments on a line and your goal is to mark as few points on a line as possible so that each segment contains at least one marked point. Problem Description Task.Given a set of n segments \(\{ [a_0, b_0], […
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KDTree模板,在m维空间中找最近的k个点,用的是欧几里德距离. 理解了好久,昨晚始终不明白那些“估价函数”,后来才知道分情况讨论,≤k还是=k,在当前这一维度距离过线还是不过线,过线则要继续搜索另一个子树.还有别忘了当前这个节点! #include<cmath> #include<queue> #include<cstdio> #include<cstring> #include<algorithm> #define read(x) x=ge…
I need some help. I have to create a function that will calculate the distance between points (x1,y1) and (x2, y2). All numbers are of type double. I keep getting incorrect output. I am usinge visual studio and C language. Here is my code. #include <…
The Moving Points Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 878    Accepted Submission(s): 353 Problem Description There are N points in total. Every point moves in certain direction and c…
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 思路: 自己脑子当机了,总是想着斜率和截距都要相同.但实际上三个点是一条直线的话只要它们的斜率相同就可以了,因为用了相同的参照点,截距一定是相同的. 大神的做法: 对每一个点a, 找出所有其他点跟a的连线斜率,相同为同一条线,记录下通过a的点的线上最大的点数. 找出每一个点的最大连线通过的点数. 其…
[题目分析] 典型的KD-Tree例题,求k维空间中的最近点对,只需要在判断的过程中加上一个优先队列,就可以了. [代码] #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include <set> #include <map> #include <string> #include <algorithm> #in…
水到家了 #include <iostream> #include <vector> #include <algorithm> using namespace std; struct Point{ int index, pos; Point(, ){ index = index_; pos = pos_; } bool operator < (const Point& a) const{ return pos < a.pos; } }; int ma…
Calculate the Distance Between Two Points in PHP There are a lot of applications where it is useful to know the distance between two coordinates. Here, you'll find a PHP function that takes the latitude and longitude of two points and returns the dis…
Applet程序. import javax.swing.*; import java.awt.*; import java.awt.geom.*; import javax.swing.event.MouseInputAdapter; import java.awt.event.MouseEvent; @SuppressWarnings("serial") public class CurveApplet extends JApplet { // Initialize the app…
Given n points on a 2D plane, find the maximum number of points that lie on the same straight line. 主要思想:O(n2),固定一个点,遍历其余 n 个点, 计算与该点相同的点的个数,和其余所有点的斜率,相同斜率的点视为同一直线. 初步 AC 代码: /** * Definition for a point. * struct Point { * int x; * int y; * Point()…
Description There is a cycle with its center on the origin. Now give you a point on the cycle, you are to find out the other two points on it, to maximize the sum of the distance between each other you may assume that the radius of the cycle will not…
同p2626.由于K比较小,所以不必用堆. #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; typedef double db; #define N 50001 #define INF 2147483647.0 #define KD 5//ά¶ÈÊý int qp[KD]; int n,root,kd,K; int dn;…
Visible Lattice Points Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5636   Accepted: 3317 Description A lattice point (x, y) in the first quadrant (x and y are integers greater than or equal to 0), other than the origin, is visible fr…
简介 Sub Points工具是 Esri 中国自主开发的一个插件,该工具优先考虑点在空间分布上的均匀合理性,并结合点数据中包含的 "优先级" 属性进行筛选.通过获取每个点在一定范围内拥有的相邻点的数目信息,得到地图中点密度的分布状况.抽稀时在若干相临近的点中首先比较优先级,保留优先级高的:优先级相同时比较 NAME 字段,保留 NAME 长度短的:两者都相同时随机选择.使用 Sub Points 进行点抽稀的数据,必须包含"优先级"和"name"…
Cool Points We have a circle of radius R and several line segments situated within the circumference of this circle. Let’s define a cool point to be a point on the circumference of this circle so that the line segment that is formed by this point and…
题目链接: E. Points on Plane time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output On a plane are n points (xi, yi) with integer coordinates between 0 and 106. The distance between the two points wi…
7.6 Given a two-dimensional graph with points on it, find a line which passes the most number of points. 这道题给了我们许多点,让我们求经过最多点的一条直线.给之前那道7.5 A Line Cut Two Squares in Half 平均分割两个正方形的直线一样,都需要自己写出点类和直线类.在直线类中,我用我们用斜率和截距来表示直线,为了应对斜率不存在情况,我们还需用一个flag来标记是否…