[题目] Given a collection of integers that might contain duplicates, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. [思路] 注意sort,使得判断临接元素是否相邻. 与leetcode78类似,多了一个重复数判断条件 if(i>flag&&nums…

引言 Coding 问题中有时会出现这样的问题:给定一个集合,求出这个集合所有的子集(所谓子集,就是包含原集合中的一部分元素的集合). 或者求出满足一定要求的子集,比如子集中元素总和为定值,子集元素个数为定值等等. 我把它们归类为子集系列问题. 这篇博文作为子集系列第一篇,着重讨论最传统的子集问题,也就是“给定一个集合,求出这个集合所有的子集”,没有附加要求.我会讨论解决此类题目的两种思路,并做一些比较. 还是从具体题目开始 例题1, 不包含重复元素的集合S,求其所有子集 Given a set…

Subsets II Given a collection of integers that might contain duplicates, nums, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If nums = [1,2,2]…

题目: Given a collection of integers that might contain duplicates, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example, If S = [1,2,2], a solution…

[题目] Given a collection of candidate numbers (candidates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target. Each number in candidates may only be used once in the combination. Note: A…

[题目] Given a set of distinct integers, nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. 求子集,无重复数 [思路] 1.有回溯法模板 2.将tmp加入进ans.tmp用来存放第i个元素的子集.回溯产生第i个元素与其后[i+1,len]元素产生的子集(i-1前已经产生过,不重复遍历).因第i…

引言 既上一篇 子集系列(一) 后,这里我们接着讨论带有附加条件的子集求解方法. 这类题目也是求子集,只不过不是返回所有的自己,而往往是要求返回满足一定要求的子集. 解这种类型的题目,其思路可以在上一篇文章的思路略作改进. 例 1,求元素数量为定值的所有子集 Combinations Given two integers n and k, return all possible combinations of k numbers out of 1 ... n. For example,If n …

1 - 从strStr谈面试技巧与代码风格 必做题: 13.字符串查找 要求:如题 思路:(自写AC)双重循环,内循环读完则成功 还可以用Rabin,KMP算法等 public int strStr(String source, String target) { if (source == null || target == null) { return -1; } char[] sources = source.toCharArray(); char[] targets = target.to…

[题目] Given a set of candidate numbers (candidates) (without duplicates) and a target number (target), find all unique combinations in candidates where the candidate numbers sums to target. The same repeated number may be chosen from candidates unlimi…

[题目] Find all possible combinations of k numbers that add up to a number n, given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers. Note: All numbers will be positive integers. The solution set must not…