1. Element-wise Multiplication * torch.Tensor.mul() torch.mul() 2. Matrix Multiplication torch.Tensor.matmul() torch.matmul() torch.Tensor.mm() torch.mm() 3. Batch Matrix Multiplication torch.bmm() torch.bmm(out_theta.transpose(1, 2), out_phi)…

PyTorch常用代码段整理合集 转自:知乎 作者:张皓 众所周知,程序猿在写代码时通常会在网上搜索大量资料,其中大部分是代码段.然而,这项工作常常令人心累身疲,耗费大量时间.所以,今天小编转载了知乎上的一篇文章,介绍了一些常用PyTorch代码段,希望能够为奋战在电脑桌前的众多程序猿们提供帮助! 本文代码基于 PyTorch 1.0 版本,需要用到以下包 import collectionsimport osimport shutilimport tqdm import numpy as np…

转自:https://github.com/ritchieng/the-incredible-pytorch The Incredible PyTorch What is this? This is inspired by the famous Awesome TensorFlow repository where this repository would hold tutorials, projects, libraries, videos, papers, books and anythi…

目录 pytorch学习 numpy & Torch Variable 激励函数 回归 区分类型 快速搭建法 模型的保存与提取 批训练 加速神经网络训练 Optimizer优化器 CNN MNIST手写数据 Reference pytorch学习 numpy & Torch import torch import numpy as np np_data = np.arange(6).reshape((2, 3)) torch_data = torch.from_numpy(np_data)…

文章目录 skip-gram pytorch 朴素实现网络结构训练过程:使用nn.NLLLoss()batch的准备,为unsupervised,准备数据获取(center,contex)的pair:采样时的优化:Subsampling降低高频词的概率skip-gram 进阶:negative sampling一般都是针对计算效率优化的方法:negative sampling和hierachical softmaxnegative sampling实现:negative sampling原理:n…

import torch import numpy as np details about math operation in torch can be found in: http://pytorch.org/docs/torch.html#math-operations convert numpy to tensor or vise versa # convert numpy to tensor or vise versa np_data = np.arange(6).reshape((2,…

基础配置 检查 PyTorch 版本 torch.__version__               # PyTorch version torch.version.cuda              # Corresponding CUDA version torch.backends.cudnn.version()  # Corresponding cuDNN version torch.cuda.get_device_name(0)   # GPU type 更新 PyTorch PyTo…

前言 PyTorch和Tensorflow是目前最为火热的两大深度学习框架,Tensorflow主要用户群在于工业界,而PyTorch主要用户分布在学术界.目前视觉三大顶会的论文大多都是基于PyTorch,如何快速入门PyTorch成了当务之急. 正文 本着循序渐进的原则,我会依次从易到难的内容进行介绍,并采用定期更新的方式来补充该文. 一.安装PyTorch 参考链接:https://blog.csdn.net/miao0967020148/article/details/80394270 安…

import torch import numpy as np # details about math operation in torch can be found in: http://pytorch.org/docs/torch.html#math-operations # convert numpy to tensor or vise versa np_data = np.arange(6).reshape((2, 3)) torch_data = torch.from_numpy(n…

torch.mul() 函数功能:逐个对 input 和 other 中对应的元素相乘. 本操作支持广播,因此 input 和 other 均可以是张量或者数字. 举例如下: >>> import torch >>> a = torch.randn(3) >>> a tensor([-1.7095, 1.7837, 1.1865]) >>> b = 2 >>> torch.mul(a, b) tensor([-3.4…

一个开源的机器学习框架,加速了从研究原型到生产部署的路径. !pip install torch -i https://pypi.tuna.tsinghua.edu.cn/simple import torch import numpy as np Basics 就像Tensorflow一样,我们也将继续在PyTorch中玩转Tensors. 从数据(列表)中创建张量 data = [[1, 2],[3, 4]] tensors = torch.tensor(data) tensors tens…

A multiplication game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6028   Accepted: 3013 Description Stan and Ollie play the game of multiplication by multiplying an integer p by one of the numbers 2 to 9. Stan always starts with p =…

                             Matrix Multiplication Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 18173   Accepted: 3912 Description You are given three n × n matrices A, B and C. Does the equation A × B = C hold true? Input The first l…

Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Problem Description Given two matrices A and B of size n×n, find the product of them. bobo hates big integers. So you are only asked to find t…

Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 820    Accepted Submission(s): 328 Problem Description Given two matrices A and B of size n×n, find the product of them. b…

A typical implementation Booth's algorithm can be implemented by repeatedly adding (with ordinary unsigned binary addition) one of two predetermined values A and S to a product P, then performing a rightward arithmetic shift on P. Let m and r be the…

http://acm.hdu.edu.cn/showproblem.php?pid=4951 2014多校 第八题 1008 2014 Multi-University Training Contest 8 Multiplication table Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 438    Accepted Submi…

hdu4920 Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 568    Accepted Submission(s): 225 Problem Description Given two matrices A and B of size n×n, find the product o…

题目链接:http://poj.org/problem?id=1651 Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one card out of the row and scores the number of points equal to the prod…

题目传送门 /* 题意:加上适当的括号,改变计算顺序使得总的计算次数最少 矩阵连乘积问题,DP解决:状态转移方程: dp[i][j] = min (dp[i][k] + dp[k+1][j] + p[i-1] * p[k] * p[j]) (i<=k<j) s[i][j] 记录断开的地方(即加括号的位置),回溯法输出结果 */ #include <cstdio> #include <cstring> #include <string> #include &l…

Matrix Chain Multiplication Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 834    Accepted Submission(s): 570 Problem DescriptionMatrix multiplication problem is a typical example of dynamical…

D - Matrix Multiplication Time Limit: 2000/1000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others) SubmitStatus Problem Description       Let us consider undirected graph G = {V; E} which has N vertices and M edges. Incidence matrix of this g…

Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1775    Accepted Submission(s): 796 Problem Description Given two matrices A and B of size n×n, find the product of them.…

Matrix Chain Multiplication Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 442 Appoint description:  System Crawler  (2015-08-25) Description   Suppose you have to evaluate an expression like A*B*C*D…

Description The multiplication puzzle is played with a row of cards, each containing a single positive integer. During the move player takes one card out of the row and scores the number of points equal to the product of the number on the card taken…

这个题思路没有任何问题,但还是做了近三个小时,其中2个多小时调试 得到的经验有以下几点: 一定学会调试,掌握输出中间量的技巧,加强gdb调试的学习 有时候代码不对,得到的结果却是对的(之后总结以下常见错误) 能用结构体,就别用数组,容易出错(暂时还不知道为什么)=>现在知道申请的数组空间在运行期间被释放,除非用malloc去申请数组 代码要规范,空格该有就要有 有些不规范表达式,不同编译器出现不同结果,注意应避免使用这类语句 像这道题主要坑在了第三点上,以后要注意避免 以下是AC代码 第一次完成…

// UVa442 Matrix Chain Multiplication // 题意:输入n个矩阵的维度和一些矩阵链乘表达式,输出乘法的次数.假定A和m*n的,B是n*p的,那么AB是m*p的,乘法次数为m*n*p // 算法:用一个栈.遇到字母时入栈,右括号时出栈并计算,然后结果入栈.因为输入保证合法,括号无序入栈   #include<cstdio> #include<stack> #include<iostream> #include<string>…

Problem Description Given two matrices A and B of size n×n, find the product of them. bobo hates big integers. So you are only asked to find the result modulo 3.   Input The input consists of several tests. For each tests: The first line contains n (…

A. Multiplication Table Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/577/problem/A Description Let's consider a table consisting of n rows and n columns. The cell located at the intersection of i-th row and j-th column co…

矩阵相乘,采用一行的去访问,比采用一列访问时间更短,根据数组是一行去储存的.神奇小代码. Matrix multiplication Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1476    Accepted Submission(s): 650 Problem Description Given two matrices A…