可以复用house robber的代码,两趟dp作为两种情况考虑,选最大值 #include <stdio.h> #define MAX 1000 #define max(a,b) ( (a)>(b)?(a):(b) ) }; int rob1(int* a, int n) { int i; dp[]=; dp[]=a[]; ;i<n;i++){ dp[i+]=max(dp[i],a[i]+dp[i-]); } return dp[n]; } int rob(int* nums,…

After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. That means the first house is the neighbor o…

213. House Robber II     Total Accepted: 24216 Total Submissions: 80632 Difficulty: Medium Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will…

House Robber题目链接 House Robber II题目链接 1. House Robber 题目要求: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjac…

House Robber II Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arrang…

House Robber:不能相邻,求能获得的最大值 House Robber II:不能相邻且第一个和最后一个不能同时取,求能获得的最大值 House Robber III:二叉树下的不能相邻,求能获得的最大值 Paint House:用3种颜色,相邻的房屋不能用同一种颜色,求花费最小 Paint House II:用k种颜色,相邻的房屋不能用同一种颜色,求花费最小Paint Fence:用k种颜色,相邻的可以用同一种颜色,但不能超过连续的2个,求有多少种可能性 198. House Robb…

House Robber II You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Mean…

After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. That means the first house is the neighbor o…

198. House Robber Total Accepted: 45873 Total Submissions: 142855 Difficulty: Easy You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing ea…

目录 题目链接 注意点 解法 小结 题目链接 Path Sum II - LeetCode 注意点 不要访问空结点 解法 解法一:递归,DFS.每当DFS搜索到新节点时,都要保存该节点.而且每当找出一条路径之后,都将这个保存为一维vector的路径保存到最终结果二维vector中.并且,每当DFS搜索到子节点,发现不是路径和时,返回上一个结点时,需要把该节点从一维vector中移除. /** * Definition for a binary tree node. * struct TreeNo…