题意:给定n个气球.每次你可以打破一个,打破第i个,那么你会获得nums[left] * nums[i] * nums[right]个积分. (nums[-1] = nums[n] = 1)求你可以获得的最大积分数. Note:You may imagine nums[-1] = nums[n] = 1. They are not real therefore you can not burst them.0 ≤ n ≤ 500, 0 ≤ nums[i] ≤ 100 Example:Input:…

Burst Balloons Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get nums[left] * nums[i] * nums[right] coins.…

2018-10-03 19:29:43 问题描述: 问题求解: 很有意思的题目,首先想到的是暴力遍历解空间,当然也用到了memo,可惜还是TLE,因为时间复杂度确实有点过高了,应该是O(n!). Map<LinkedList, Integer> map = new HashMap<>(); public int maxCoins(int[] nums) { if (nums.length == 0) return 0; LinkedList<Integer> list…

这道题目做了两个晚上,发现解题思路的优化过程非常有代表性.文章详细说明了如何从回溯解法改造为分治解法,以及如何由分治解法过渡到动态规划解法.解法的用时从 超时 到 超过 95.6% 提交者,到超过 99.8% 提交者.现整理下来分享给大家,如有错误评论区欢迎指正! 题目如下: 回溯法 刚看到这个题目,脑中可以很轻易的想象出解空间的结构:一个n层的数组,每层的元素相同,我们从第一层走到第n层,每层走动时不能使用之前走过的元素.然后按照规则计算获取的金币,我们尝试所有可以走的路径并记录下每条路径所能…

Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get nums[left] * nums[i] * nums[right] coins. Here left and r…

原题链接在这里:https://leetcode.com/problems/burst-balloons/ 题目: Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get…

Problem UVA1627-Team them up! Total Submissions:3577  Solved:648 Time Limit: 3000 mSec Problem Description It’s frosh week, and this year your friends have decided that they would initiate the new computer science students by dropping water balloons…

参考:LeetCode 312. Burst Balloons(戳气球) java代码如下 class Solution { //参考:https://blog.csdn.net/jmspan/article/details/51208865 public int maxCoins(int[] nums) { int[] balls = new int[nums.length+2]; balls[0] = 1; balls[balls.length - 1] = 1; int[][] coins…

Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon i you will get nums[left] * nums[i] * nums[right] coins. Here left and r…

Given n balloons, indexed from 0 to n-1. Each balloon is painted with a number on it represented by array nums. You are asked to burst all the balloons. If the you burst balloon iyou will get nums[left] * nums[i] * nums[right]coins. Here left and rig…