Poj2531 首先把所有节点都放在一组,然后采用深度优先搜索的方法,对每一个节点都做判断是否应该移到另一组去,判断的依据是移过去和不移过去哪个得到的和值比较大(这里移去B组后的计算方法就是加上该点和在A组中的所有点的间距,和减去原本就在B组中的所有点的间距),如果移过去变小了,那么则不移过去,并剪掉该条支路. import java.util.*; public class Main1 { static int ans=0; static int map[][]; static boolean…
题目难度:Medium 题目: Given an array S of n integers, are there elements a, b, c, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target. Note: The solution set must not contain duplicate quadrup…
题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 翻译: 给定一组整数,两个数字的返回索引,它们的和会等于一个特定…
题目: Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. 翻译: 给定一组整数,两个数字的返回索引,它们的和会等于一个特定…