The old lady sits on a mobile chair every morning.The book contains scandalous text. The current survey will have a wider geographical spread.His rustic speech and ways made him uncomfortable in the city school.他土里土气的语言和生活方式使他在城里的中学感到不舒服.I'm afraid t…

古诗背诵 要求:根据诗句,先翻译成现代文,然后绘制图像. 词汇系列 要求:认真朗读单词,然后通过该单词联想2个词汇,然后给每个单词造句. 例子:class班级,联想到了classroom教室,classmate同学,course课程,blackboard黑板,teacher老师. 句子系列 要求:朗读下面句子,然后让后认真翻译,然后朗读. Mr.Brown is an engineer. Gradualy he became silent. She remained standing for a…

在一些项目中可能需要对一段字符串中的单词进行统计,我在这里写了一个简单的demo,有需要的同学可以拿去看一下. 本人没怎么写个播客,如果有啥说的不对的地方,你来打我啊 不说废话了直接贴代码: 实现代码: /** * 统计各个单词出现的次数 * @param text */ public static void findEnglishNum(String text){ //找出所有的单词 String[] array = {".", " ", "?"…

要求: 确保字符串的每个单词首字母都大写,其余部分小写. 这里我自己写了两种方法,或者说是一种方法,另一个是该方法的变种. 第一种: function titleCase(str) { var newarr,newarr1=[]; newarr = str . toLowerCase() . split(" "); for(var i = 0 ; i < newarr . length ; i++){ newarr1 . push(newarr[i][0] . toUpperCa…

3172: [Tjoi2013]单词 Time Limit: 10 Sec  Memory Limit: 512 MBSubmit: 3198  Solved: 1532[Submit][Status][Discuss] Description 某人读论文,一篇论文是由许多单词组成.但他发现一个单词会在论文中出现很多次,现在想知道每个单词分别在论文中出现多少次. Input 第一个一个整数N,表示有多少个单词,接下来N行每行一个单词.每个单词由小写字母组成,N<=200,单词长度不超过10^6…

Given a list of words (without duplicates), please write a program that returns all concatenated words in the given list of words. A concatenated word is defined as a string that is comprised entirely of at least two shorter words in the given array.…

Given a set of words (without duplicates), find all word squares you can build from them. A sequence of words forms a valid word square if the kth row and column read the exact same string, where 0 ≤ k < max(numRows, numColumns). For example, the wor…

Given a sequence of words, check whether it forms a valid word square. A sequence of words forms a valid word square if the kth row and column read the exact same string, where 0 ≤k < max(numRows, numColumns). Note: The number of words given is at le…

A string such as "word" contains the following abbreviations: ["word", "1ord", "w1rd", "wo1d", "wor1", "2rd", "w2d", "wo2", "1o1d", "1or1", "…

Given a non-empty string s and an abbreviation abbr, return whether the string matches with the given abbreviation. A string such as "word" contains only the following valid abbreviations: ["word", "1ord", "w1rd", &…