链接:https://ac.nowcoder.com/acm/contest/993/C来源:牛客网 题目描述 Farmer John recently bought another bookshelf for the cow library, but the shelf is getting filled up quite quickly, and now the only available space is at the top. FJ has N cows (1 <= N <= 20)…

Red and Black Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12519    Accepted Submission(s): 7753 Problem Description There is a rectangular room, covered with square tiles. Each tile is color…

题目: 简单dfs,没什么好说的 代码: #include <iostream> using namespace std; typedef long long ll; #define INF 2147483647 int w,h; ][]; ][] = {-,,,,,-,,}; ; void dfs(int x,int y){ || x >= h || y < || y >= w || a[x][y] == '#') return; ans++; a[x][y] = '#';…

题目在这里 题意 : 问你按照图中所给的提示走,多少步能走出来??? 其实只要根据这个提示走下去就行了.模拟每一步就OK,因为下一步的操作和上一步一样,所以简单dfs.如果出现loop状态,只要记忆每个所到的点的第一次的步数,最后总步数减掉它即可 /************************************************************************* > File Name: poj1573.cpp > Author: YeGuoSheng >…

POJ1979 Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can mo…

LINK 题意:给出n个数,\(a_i\)代表下一步会移动到第\(a_i\)个位置,并继续进行操作,\(b_i\)1代表进行一次翻面操作,要求不管以哪个位置上开始,最后都能满足 1.到达过所有位置 2.对到达的任意位置,都已经进行过奇次和偶次翻面操作 交换任意两个\(a_i\),或修改\(b_i\)的值算做一次操作 问最小操作数. 思路:首先可以知道,要满足条件1,必须使该排列的循环节长度为1(即所有数成一个环),再者要满足条件2,则\(b_i==1\)必须有奇数个. 那么很简单,对所有未标记的…

这道题看上去非常麻烦,什么迷宫啊.门之类的,事实上挺简单的,就是让把与 * 连通的都置为 # 包含 * , 直接dfs就能够了,只是我wa了好多次...最后居然是多读了一个换行.忘了加getchar()了,gets()函数 会把缓冲区里面的换行给读进去的...应该把换行去掉,血的教训啊.. . 代码: #include<stdio.h> #include<string.h> #include<stdlib.h> int dx[4]={-1,0,0,1}; int dy[…

Lake Counting Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 18201   Accepted: 9192 Description Due to recent rains, water has pooled in various places in Farmer John's field, which is represented by a rectangle of N x M (1 <= N <= 100…

Problem Description There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can mo…

原题链接:点击!   大致题意:白块表示可以放置炮台的位置——每个炮台可以攻击到上下左右的直线上的炮台(也就是说在它的上下左右直线上不可以再放置炮台,避免引起互相攻击),黑块表示隔离墙的位置——不可放置并且可以阻挡炮火:求对于一个最大4*4的格子来说,最大的放置炮台的个数是多少. 简单分析: 简单的dfs();由于本题地图很小,不用考虑太多,尽情暴力即可.先把DFS枝干画出来,然后枝叶就用函数来具体实现. AC代码:(附注释) #include <iostream> #include<s…