1132 Cut Integer(20 分) Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devid…

1132 Cut Integer (20 分)   Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be de…

1132 Cut Integer(20 分) Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devid…

https://pintia.cn/problem-sets/994805342720868352/problems/994805347145859072 Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 an…

题目 Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, afer cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of…

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…

Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…

题意:略. 思路:注意除数可能为0的情况,不然会导致浮点错误. 代码: #include <iostream> #include <string> using namespace std; int main() { int n; string str; cin>>n; while(n--){ cin>>str; ,str.size()/); ,str.size()/); int a=stoi(s1),b=stoi(s2),val=stoi(str); &am…

Source: PAT A1132 Cut Integer (20 分) Description: Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting…

1132. Cut Integer (20) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we ha…

PAT甲级1103. Integer Factorization 题意: 正整数N的K-P分解是将N写入K个正整数的P次幂的和.你应该写一个程序来找到任何正整数N,K和P的N的K-P分解. 输入规格: 每个输入文件包含一个测试用例,它给出一行三个正整数N(<= 400), K(<= N)和P(1 <P <= 7).一行中的数字用空格分隔. 输出规格: 对于每种情况,如果解决方案存在,输出格式如下: N = n1 ^ P + ... nK ^ P 其中ni(i = 1,... K)是…

Cut Integer PAT-1132 #include<iostream> #include<cstring> #include<string> #include<algorithm> #include<cstdio> #include<sstream> #include<cstdlib> using namespace std; int main(){ int n; cin>>n; while(n--){…

Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…

Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note: Assume we are dealing with an environment which could only store integers within…

这道题是LeetCode里的第7道题. 题目描述: 给出一个 32 位的有符号整数,你需要将这个整数中每位上的数字进行反转. 示例 1: 输入: 123 输出: 321  示例 2: 输入: -123 输出: -321 示例 3: 输入: 120 输出: 21 注意: 假设我们的环境只能存储得下 32 位的有符号整数,则其数值范围为 [−231,  231 − 1].请根据这个假设,如果反转后整数溢出那么就返回 0. 首先,这是一道简单题,根据我多年的做题经验来看,这道题肯定有坑,绝对会有 IN…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:整数,反转,题解,Leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 转成字符串 数学 日期 题目地址:https://leetcode.com/problems/reverse-integer/description/ 题目描述 Given a 32-bit signed integer, reverse d…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows. int reverse(int x) { if(x == INT_MIN){//-2147483648 ;…

The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K and P. Input Specification: Each in…

https://pintia.cn/problem-sets/994805342720868352/problems/994805357258326016 Given a set of N (>) positive integers, you are supposed to partition them into two disjoint sets A​1​​ and A​2​​ of n​1​​ and n​2​​ numbers, respectively. Let S​1​​ and S​…

本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90574720 1103 Integer Factorization (30 分)   The K−P factorization of a positive integer N is to write N as the sum of the P-th power of K positive integers. You are supposed to write…

问题描述 Example1: x = 123, return 321 Example2: x = -123, return -321 原题链接: https://leetcode.com/problems/reverse-integer/ 解决方案 public int reverse(int x) { long res = 0; //need to consider the overflow problem while(x != 0){ res = res * 10 + x % 10; //…

Given a set of N (>) positive integers, you are supposed to partition them into two disjoint sets A​1​​ and A​2​​ of n​1​​and n​2​​ numbers, respectively. Let S​1​​ and S​2​​ denote the sums of all the numbers in A​1​​ and A​2​​, respectively. You ar…

The K−P factorization of a positive integer N is to write N as the sum of the P-th power of Kpositive integers. You are supposed to write a program to find the K−P factorization of N for any positive integers N, K and P. Input Specification: Each inp…

题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805364711604224 题意: 给定一个数n,要求从1~n中找出k个数,使得这些数的p次方之和等于n 思路: 因为n为400,所以dfs加剪枝[本来还在想dp来着] 他要求输出的方案是数字之和最大的,如果之和相等要输出字典序较大的. 所以还需维护一个数字之和. 一个剪枝的方法是从大到小进行dfs,后面被选的数一定比前面被选的要小,这里不限制的话显然会出现重复.…

大模拟题,按要求建立多边形,先定位斜边的位置,再分类讨论~ #include<bits/stdc++.h> using namespace std; ; struct node { double x,y; }Node[][maxn]; double distance (node a,node b) { return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)); } int isXiebian (node a,node b) { ; ; } dou…

1132 Cut Integer(20 分) 题意:将一个含K(K为偶数)个数字的整数Z割分为A和B两部分,若Z能被A*B整除,则输出Yes,否则输出No. 分析:当A*B为0的时候,不能被Z整除,输出No.否则会出现浮点错误. #include<cstdio> #include<cstring> #include<cstdlib> #include<string> #include<algorithm> #include<map>…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…

字符串处理题 目录 <算法笔记> 重点摘要 1001 A+B Format (20) 1005 Spell It Right (20) 1108 Finding Average (20) 1132 Cut Integer (20) 1140 Look-and-say Sequence <算法笔记> 3.6 字符串处理 重点摘要 注意分析输入输出格式 注意细节和边界情况 1001 A+B Format (20) #include<iostream> using names…