题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4772 题面: Zhuge Liang's Password Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1404 Accepted Submission(s): 926 Problem Description In the anc…
题意:给你两个矩阵,一个矩阵旋转90度,180度,270度, 然后和另外一个矩阵进行比较,如果对应值相同,则加一,最后得出最大的值 题目没什么难度....主要是纪念下....貌似这一题是当时比赛前一个晚上做出来的 AC代码: #include<iostream> #include<cstdio> using namespace std; int a[31][31],b[31][31]; int main() { int N;int i,j,m,n; while(scanf(&quo…
Zhuge Liang's Password Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 59 Accepted Submission(s): 47 Problem Description In the ancient three kingdom period, Zhuge Liang was the most famous a…
Saving HDU Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7194 Accepted Submission(s): 3345 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏的商人,XHD不会坐以待毙的. 一天,当他正在苦思冥想解困良策的…
http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…
Special equations Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4569 Description Let f(x) = a nx n +...+ a 1x +a 0, in which a i (0 <= i <= n) are all known integers. We call f(x) 0 (mod…
The kth great number Time Limit:1000MS Memory Limit:65768KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4006 Description Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round Xiao Ming can choose to write down a nu…