Codeforces Round #234 (Div. 2) E:http://codeforces.com/problemset/problem/400/E 题意:给你n个数,然后每相邻的两个数可以通过and运算生成一个新的数,然后这些新生成的n-1个数每相邻的两个数又通过and运算成n-2个数,最后只会剩下一个数,然后让你求这n(n+1)/2个数的和,然后每一次会更新最底层的某个数,然后操作之后,输出刚才的总和. 题解:这一题,虽然是看题解,然后自己敲出来的,但是还是有点成就感和收获.首先,…

题目链接 给出n个数, 定义a[1][i]为这初始的n个数, 然后a[i][j] = a[i-1][j]&a[i-1][j-1], 这样就可以得到一个三角形一共n*(n-1)/2个数. 给出一种操作, 将a[1][x]这个位置的数换为y, 然后求换完之后的这n(n-1)/2个数的和. 很有意思的题, 这个题应该按位建线段树, 这样需要建18棵, 因为a[1][i]的最大值为1e5. 然后我们来看具体如何做, 我们来看一组数据:3 6 7, 换为二进制之后是下面这个样子. 0 1 1 1 1 0…

E. Inna and Binary Logic time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Inna is fed up with jokes about female logic. So she started using binary logic instead. Inna has an array of n ele…

A - Inna and Choose Options Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Description There always is something to choose from! And now, instead of "Noughts and Crosses", Inna choose a very unusual upgrade of…

Welcome back!    This post deals with the second half of pixel processing, the “join phase”. The previous phase was all about taking a small number of input streams and turning them into lots of independent tasks for the shader units. Now we need to…

继上篇文章介绍完了HashMap,这篇文章开始介绍Map系列另一个比较重要的类TreeMap. 大家也许能感觉到,网络上介绍HashMap的文章比较多,但是介绍TreeMap反而不那么多,这里面是有原因:一方面HashMap的使用场景比较多:二是相对于HashMap来说,TreeMap所用到的数据结构更为复杂. 废话不多说,进入正题. 签名(signature) public class TreeMap<K,V> extends AbstractMap<K,V> implement…

An apparatus and method is described herein for providing robust speculative code section abort control mechanisms. Hardware is able to track speculative code region abort events, conditions, and/or scenarios, such as an explicit abort instruction, a…

A method and apparatus for preserving memory ordering in a cache coherent link based interconnect in light of partial and non-coherent memory accesses is herein described. In one embodiment, partial memory accesses, such as a partial read, is impleme…

Logic BIST is crucial for many applications, in particular for life-critical and mission-critical applications. Logic BIST不需要在ATE上进行测试,减小了成本,但是电路本身是可能存在问题的,导致测试逻辑有问题而且增加了逻辑. Basic concepts and design rules of logic BIST Test pattern generation(exhaus…

Problem: Given a binary tree where all the right nodes are either leaf nodes with a sibling (a left node that shares the same parent node) or empty, flip it upside down and turn it into a tree where the original right nodes turned into left leaf node…