题目传送门 /* 二分查找/暴力:先埃氏筛选预处理,然后暴力对于每一行每一列的不是素数的二分查找最近的素数,更新最小值 */ #include <cstdio> #include <cstring> #include <algorithm> using namespace std; ; ; const int INF = 0x3f3f3f3f; int a[MAXN][MAXN]; int mn_r[MAXN]; int mn_c[MAXN]; bool is_prim…

题目传送门 /* 数论/暴力:找出第一次到a1,a2的次数,再找到完整周期p1,p2,然后以2*m为范围 t1,t2为各自起点开始“赛跑”,谁落后谁加一个周期,等到t1 == t2结束 详细解释:http://blog.csdn.net/u014357885/article/details/46044287 */ #include <cstdio> #include <algorithm> #include <cstring> #include <iostream…

题目传送门 /* 暴力:每次更新该行的num[],然后暴力找出最优解就可以了:) */ #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #include <string> using namespace std; ; const int INF = 0x3f3f3f3f; int a[MAXN][MAXN]; int num[MAXN];…

题目传送门 /* 暴力:O (n^2) */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #include <vector> using namespace std; ; const int INF = 0x3f3f3f3f; int main(void) //Codeforces Round #183 (Div. 2) A. Pythago…

题目传送门 /* 数学/暴力:只要一个数的最后三位能被8整除,那么它就是答案:用到sprintf把数字转移成字符读入 */ #include <cstdio> #include <algorithm> #include <cstring> #include <iostream> #include <cmath> #include <vector> using namespace std; ; const int INF = 0x3f3…

题目传送门 /* 构造+暴力:按照题目意思,只要10次加1就变回原来的数字,暴力枚举所有数字,string大法好! */ /************************************************ Author :Running_Time Created Time :2015-8-3 8:43:02 File Name :A.cpp *************************************************/ #include <cstdio>…

A. Beautiful Year time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after t…

任意门:http://codeforces.com/contest/1118/problem/C C. Palindromic Matrix time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Let's call some square matrix with integer values in its cells palind…

二分要删除几个,然后暴力判定. #include<cstdio> #include<cstring> using namespace std; int a[200010],n,m; char s1[200010],s2[200010]; bool cant[200010]; bool check(int x) { memset(cant,0,sizeof(cant)); for(int i=1;i<=x;++i) cant[a[i]]=1; int j=1; for(int…

题目链接:http://www.codeforces.com/problemset/problem/271/A题意:给你一个四位数,求比这个数大的最小的满足四个位的数字不同的四位数.C++代码: #include <iostream> #include <algorithm> using namespace std; bool chk(int x) { ]; ; i < ; i ++) { a[i] = x % ; x /= ; } sort(a, a + ); ; i &l…