[LeetCode] 148. Sort List 解题思路】的更多相关文章

Sort a linked list in O(n log n) time using constant space complexity. 问题:对一个单列表排序,要求时间复杂度为 O(n*logn),额外空间为 O(1). O(n*logn) 时间排序算法,无法是 quick sort, merge sort, head sort.quick sort 需要灵活访问前后元素,适合于数组,merge sort 只需要从左到右扫过去即可,可用于列表结构. 当列表元素个数大于2时,将列表拆分为左右…
leetcode 148. Sort List 提交网址: https://leetcode.com/problems/sort-list/  Total Accepted: 68702 Total Submissions: 278100 Difficulty: Medium  ACrate: 24.7% Sort a linked list in O(n log n) time using constant space complexity. 由于需要使用常量空间,即S(n)=O(1),故需要…
Sort a linked list in O(n log n) time using constant space complexity. 解题思路: 归并排序.快速排序.堆排序都是O(n log n),由于优先级队列是用堆排序实现的,因此,我们使用优先级队列即可,JAVA实现如下: public ListNode sortList(ListNode head) { if(head==null||head.next==null) return head; Queue<ListNode> pQ…
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution. For example, given array S = {-1 2…
Given a string containing just the characters '(' and ')', find the length of the longest valid (well-formed) parentheses substring. For "(()", the longest valid parentheses substring is "()", which has length = 2. Another example is &…
There are N gas stations along a circular route, where the amount of gas at station i is gas[i]. You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an e…
Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [-2,1,-3,4,-1,2,1,-5,4],the contiguous subarray [4,-1,2,1] has the largest sum = 6. 问题: 给定一个元素有正有负的数组,求最大连续子数组的和. 思路…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/sort-list/description/ 题目描述 Sort a linked list in O(n log n) time using constant space complexity. Example 1: Input: 4->2->1->3 Output…
Sort a linked list using insertion sort. 问题:实现单向链表的插入排序. 这是比较常规的一个算法题目. 从左往右扫列表,每次将指针的下一个元素插入前面已排好序的对应位置中. 需要注意的一定是,列表只能定位下一个元素,不能定位前一个元素,所有,每次插入位置的适合,都是对左右指针的下一个元素进行操作. void insertSort(ListNode* p1, ListNode* p2){ ListNode* next2 = p2->next; p2->ne…
Sort a linked list in O(n log n) time using constant space complexity. Example 1: Input: 4->2->1->3 Output: 1->2->3->4 Example 2: Input: -1->5->3->4->0 Output: -1->0->3->4->5 常见排序方法有很多,插入排序,选择排序,堆排序,快速排序,冒泡排序,归并排序…