题目链接 https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=4923 problem description Last night, Kingdom of Light was attacked by Kingdom of Dark! The queen of Kingdom of Light, Queen Ar, was ca…
Description 比特集合是一种抽象数据类型(Abstract Data Type) ,其包含一个集合S,并支持如下几种操作: INS M : 将元素 M 插入到集合S中: DEL M : 将集合S中所有等于 M 的元素删除: ADD M : 将集合S中的所有元素都增加数值M : QBIT k : 查询集合中有多少个元素满足其二进制的第 k位为 1 . 初始时,集合S为空集.请实现一个比特集合,并对于所有的QBIT操作输出相应的答案. Input 输入第一行包含一个正整数N,表示操作的数目…
The k-th Largest Group Time Limit: 2000MS Memory Limit: 131072K Total Submissions: 8353 Accepted: 2712 Description Newman likes playing with cats. He possesses lots of cats in his home. Because the number of cats is really huge, Newman wants to g…
题目链接 Problem Description Let’s play a game.We add numbers 1,2...n in increasing order from 1 and put them into some sets.When we add i,we must create a new set, and put iinto it.And meanwhile we have to bring [i-lowbit(i)+1,i-1] from their original s…
Triple Time Limit: 12000/6000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 388 Accepted Submission(s): 148 Problem Description Given the finite multi-set A of n pairs of integers, an another finite multi-set B …
题中给出了第 i 头牛前面有多少比它矮,如果正着分析比较难找到规律.因此,采用倒着分析的方法(最后一头牛的rank可以直接得出),对于第 i 头牛来说,它的rank值为没有被占用的rank集合中的第A[i]+1大数.所以,采用树状数组维护0-1序列(表示是否被占用)的前缀和,每次再用二分得出第K大数的下标即可. 代码如下: #include <cstdio> #include <algorithm> #include <iostream> using namespace…
题目链接:[http://acm.split.hdu.edu.cn/showproblem.php?pid=5517] 题意:定义multi_set A<a , d>,B<c , d , e>,C<x , y , z>,给出 A , B ,定义 C = A * B = ={⟨a,c,d⟩∣⟨a,b⟩∈A, ⟨c,d,e⟩∈B and b=e} .求出C之后,求C中一个元素t[i]<a , b , c>是否存在一个元素tmp<x , y , z>使…
MEG-Megalopolis 题目描述 Byteotia has been eventually touched by globalisation, and so has Byteasar the Postman, who once roamedthe country lanes amidst sleepy hamlets and who now dashes down the motorways. But it is those strolls inthe days of yore that…