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1 题目 Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. Hide Tags Tree Depth-first Search   2 思路 好久没做树的题目了,选了一道最简单的树的…
Palindrome Number Total Accepted: 19369 Total Submissions: 66673My Submissions Determine whether an integer is a palindrome. Do this without extra space. 推断一个数整数是不是回文?比如121,1221就是回文,好吧,直接利用前面写过的[Leet Code]Reverse Integer--"%"你真的懂吗? 只是这里要考虑翻转后,数值…
100. Same Tree Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. Subscribe to see which companies asked this questio…
100. Same Tree /** * Definition for a binary tree node. * function TreeNode(val) { * this.val = val; * this.left = this.right = null; * } */ /** * @param {TreeNode} p * @param {TreeNode} q * @return {boolean} */ var isSameTree = function(p, q) { if(p…
问题描述: 出现这个错误一般在WEB或者在Proxmox VE的服务器上面能看到日志: PVE中出现TASK ERROR: command 'apt-get update' failed: exit code 100 这个错误出现的原因是由于企业版软件源需要付费订阅才可以访问. 我们用到的是免费开源版的,所以更新就会提示错误. 未订阅用户如果需要更新Proxmox可以使用 Proxmox VE无订阅存储库. 在官方包存储库这里有说明:https://pve.proxmox.com/wiki/Pa…
100. same tree 100. Same Tree Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical and the nodes have the same value. Example 1: Input: 1 1 / \ / \…
100. Same Tree Total Accepted: 100129 Total Submissions: 236623 Difficulty: Easy Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have t…
100. Same Tree Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical and the nodes have the same value. Example 1: Input: 1 1 / \ / \ 2 3 2 3 [1,2,3]…
Leet Code编程题 希望能从现在开始,有空就做一些题,自己的编程能力太差了. 771 宝石与石头 简单题 应该用集合来做 给定字符串J 代表石头中宝石的类型,和字符串 S代表你拥有的石头. S 中每个字符代表了一种你拥有的石头的类型,你想知道你拥有的石头中有多少是宝石. J 中的字母不重复,J 和 S中的所有字符都是字母.字母区分大小写,因此"a"和"A"是不同类型的石头. 示例 1: 输入: J = "aA", S = "aAA…
100. Same Tree class Solution { public: bool isSameTree(TreeNode* p, TreeNode* q) { if(p == NULL && q == NULL) return true; else if(p == NULL || q == NULL) return false; if(p->val != q->val) return false; return isSameTree(p->left,q->l…
描述:递归 代码: class Solution: # @param num, a list of integers # @return a tree node def sortedArrayToBST(self, num): if len(num) == 0: return None mid_index = len(num) / 2 tmp_tree = TreeNode(num[mid_index]) tmp_tree.left = self.sortedArrayToBST(num[:mi…
语言:Python 描述:使用递归实现 # Definition for a binary tree node # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: # @param p, a tree node # @param q, a tree node # @return a boolean def isSameTre…
题目: Invert a binary tree. 4 / \ 2 7 / \ / \ 1 3 6 9 to 4 / \ 7 2 / \ / \ 9 6 3 1 思路分析: 题意是将二叉树全部左右子数对调,如上图所看到的. 详细做法是,先递归处理左右子树,然后将当前的左右子树对调. 代码实现: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeN…
描述:递归调用,getMax返回 [节点值,经过节点左子节点的最大值,经过节点右节点的最大值],每次递归同时查看是否存在不经过节点的值大于max. 代码:待优化 def getLargeNode(self, a, b): if a and b: return max(a, b) elif a and not b: return a elif not a and b: return b else: tmp = None def getMax(self, node): if node is None…
语言:Python 描述:使用递归实现 class Solution: # @return an integer def numTrees(self, n): : elif n == : else: part_1 = self.numTrees(n-) * part_2 = ,n-): part_left = self.numTrees(i) part_right = self.numTrees(n - - i) part_2 += part_left * part_right return p…
题目链接:Same Tree | LeetCode OJ Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. Tags: Depth-first Search 分析 很基本的一道深度优…
------------------------------------------ 递归比较即可 AC代码: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public boolean isSa…
[题目] Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. [解题] 思路: 这道题要判断树形一样,在这个基础上val一样. 共有5种树型: 1. node为null 2. node…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 给出两个二叉树,写一个方法判断两个二叉树是否相等, 如果两个二叉树相等,说明结构相同并且每个节点的值相同. 如果两个节点都为空,则说…
题目来源 https://leetcode.com/problems/same-tree/ Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 题意分析 Input: twon bin…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 判断两棵树是否相同. 很简单.递归. /** * Definition for a binary tree node. * publ…
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public boolean isSameTree(TreeNode p, TreeNode q) { if(p==null|| q==null) r…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. Solution 1:recursion,the key is to find out all situations of retu…
题目描述: Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 解题思路: 递归调用比较左子树和右子树以及该节点. 代码描述: /** * Definition for a binar…
描述:注意需要先self.connect(right)再self.connect(left),否则会有case通不过,原因是左边递归执行时依赖与右边的next已经建立,而先执行connect(left)的话右边还没有完成关系的建立. 代码: class Solution: # @param root, a tree node # @return nothing def doSth(self, nextNode, conNode): while nextNode is not None: if n…
描述:计算逆波兰表达法的结果 Sample: [", "*"] -> ((2 + 1) * 3) -> 9 [", "/", "+"] -> (4 + (13 / 5)) -> 6 使用stack实现: def is_op(c): return c in ['+', '-', '*', '/'] def divide(x, y): if (x * y) < 0: return -1 * ((-x)…
语言:Python 描述:使用递归实现 def getList(self, node): if node is None: return [] if node.left is None and node.right is None: return [[node.val]] result = [] for item in self.getList(node.left): result.append([node.val] + item) for item in self.getList(node.r…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 很简单,直接上代码: /** * Definition for a binary tree node. * public class…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 题意大概是:给定两个二叉树,编写一个函数检查它们是否相等.如果结构相同且节点具有相同的值,则两个二叉树被认为是相等的. 题目给出了树…
Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value.  题目标题:Tree 这道题目给了我们两个二叉树,让我们判断这两个二叉树是否一摸一样.利用preOrder 来遍历tree, 对于每…