206. Reverse Linked List 之前在牛客上的写法: 错误代码: class Solution { public: ListNode* ReverseList(ListNode* pHead) { if(pHead == NULL) return NULL; ListNode* p1 = pHead; ListNode* p2 = pHead->next; ListNode* p3 = pHead->next->next; pHead->next = NULL;…

表不支持随机查找,通常是使用next指针进行操作. 206. 反转链表 /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ //时间:O(n) 只遍历了一遍链表 //空间:O(1) 开了三个指针的空间 class Solution { public: ListNode*…

206. Reverse Linked List[easy] Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 解法一: class Solution { public: ListNode* reverseList(ListNode* head) { ListNode * pre = NULL;…

Question 206. Reverse Linked List Solution 题目大意:对一个链表进行反转 思路: Java实现: public ListNode reverseList(ListNode head) { ListNode newHead = null; while (head != null) { ListNode tmp = head.next; head.next = newHead; newHead = head; head = tmp; } return new…

Reverse Linked List,一道有趣的题目.给你一个链表,输出反向链表.因为我用的是JavaScript提交,所以链表的每个节点都是一个对象.例如1->2->3,就要得到3->2->1. 1.数组构造 一个很容易想到的方法是用数组保存新构造每个节点,然后反向构造链表,输出: var reverseList = function(head) { var ans = []; while (head) { var node = new ListNode(head.val);…

Reverse Linked List Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 解法一:非递归 /** * Definition for singly-linked list. * struct ListNode { * int va…

Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 反向链表,分别用递归和迭代方式实现. 递归Iteration: 新建一个node(value=任意值, next = None), 用一个变量 next 记录head.next,head.next指向新node.next,新 node.next…

Reverse Linked List 描述 反转一个单链表. 示例: 输入: 1->2->3->4->5->NULL    输出: 5->4->3->2->1->NULL 进阶: 你可以迭代或递归地反转链表.你能否用两种方法解决这道题? 解析 设置三个节点pre.cur.next (1)每次查看cur节点是否为NULL,如果是,则结束循环,获得结果 (2)如果cur节点不是为NULL,则先设置临时变量next为cur的下一个节点 (3)让cur…

要求 反转一个链表 不得改变节点的值 示例 head->1->2->3->4->5->NULL NULL<-1<-2<-3<-4<-5<-head 思路 设置三个辅助指针 实现 50实现反转,51-52实现后移 1 #include <iostream> 2 using namespace std; 3 4 struct ListNode { 5 int val; 6 ListNode *next; 7 ListNode(…

Reverse a singly linked list. 解题思路: 用Stack实现,JAVA实现如下: public ListNode reverseList(ListNode head) { if(head==null) return null; Stack<ListNode> stack =new Stack<ListNode>(); ListNode temp=head; while(temp!=null){ stack.push(temp); temp=temp.ne…