#include <iostream> using namespace std;const int MOD = 1000;//像这样的一个常量就应该专门定义一下 int PowMod(int a, int n)//a^n%MOD { int ret = 1; while(n) { if(n & 1) ret = ret * a % MOD; //变为二进制,然后就可以专门进行分解计算,十分的方便,要求是结合位运算一同使用 a = a * a % MOD; //这里要求特别的注意,因为是…
题目链接:https://vjudge.net/problem/HDU-5950 Recursive sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2727 Accepted Submission(s): 1226 Problem Description Farmer John likes to play mat…
题目链接:传送门 题目: Recursive sequence Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description Farmer John likes to play mathematics games with his N cows. Recently, they are attracted…