也许更好的阅读体验 \(\mathcal{Description}\) \(t\)组询问,每次询问\(l,r,k\),问\([l,r]\)内有多少数与\(k\)互质 \(0<l<=r<=10^{15},k<=10^{9},t<=100\) \(\mathcal{Solution}\) 考虑 容斥 先求\([l,r]\)内出有多少数与\(k\)不互质,再用总数减去即可 将\(k\)质因子分解为\(p_1^{k_1}·p_2^{k_2}·...p_n^{k_n}\) 在\([l,…

[HDU4135]Co-prime 题意 给出三个整数N,A,B.问在区间[A,B]内,与N互质的数的个数.其中N<=10^9,A,B<=10^15. 分析 容斥定理的模板题.可以通过容斥定理求出[1,n]与x互质的数的个数.方法是先将x进行质因子分解,然后对于每个质因子pi,[1,n]内可以被pi整除的数目为n/pi.可以通过容斥定理解决逆命题,既[1,n]与x不互质的数目.n/p1+n/p2+n/p3-n/p1p2-n/p1p3-n/p2p3+n/p1p2p3.既奇数是加,偶数是减.具体的…

Description: Count the number of prime numbers less than a non-negative number, n click to show more hints. Credits:Special thanks to @mithmatt for adding this problem and creating all test cases. 求n以内的所有素数,以前看过的一道题目,通过将所有非素数标记出来,再找出素数,代码如下: public i…

Peter wants to generate some prime numbers for his cryptosystem. Help him! Your task is to generate all prime numbers between two given numbers! Input The input begins with the number t of test cases in a single line (t<=10). In each of the next t li…

Sum of Consecutive Prime Numbers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 20050   Accepted: 10989 Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representatio…

传送门 Description A ring is composed of n (even number) circles as shown in diagram. Put natural numbers 1, 2, . . . , n into each circle separately, and the sum of numbers in two adjacent circles should be a prime. Note: the number of first circle sho…

题意为给出两个四位素数A.B,每次只能对A的某一位数字进行修改,使它成为另一个四位的素数,问最少经过多少操作,能使A变到B.可以直接进行BFS搜索 #include<bits/stdc++.h> using namespace std; bool isPrime(int n){//素数判断 || n == ) return true; else{ ; ; i < k; i++){ ) return false; } return true; } } ]; ]; void getPrime…

hdu5901题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5901 code vs 3223题目链接:http://codevs.cn/problem/3223/ 思路:主要是用了一个Meisell-Lehmer算法模板,复杂度O(n^(2/3)).讲道理,我不是很懂(瞎说什么大实话....),下面输出请自己改 #include<bits/stdc++.h> using namespace std; typedef long long LL;…

题意:在n个星球,每2个星球之间的联通需要依靠一个网络适配器,每个星球喜欢的网络适配器的价钱不同,先给你一个n,然后n个数,代表第i个星球喜爱的网络适配器的价钱,然后给出一个矩阵M[i][j]代表第i个星球到第j个星球联通所需的价钱,求联通所有星球所需的最小价钱 思路:prime 每次加入一条边的时候把边2个点的权值加进去即可 (zoj崩了,题也没法交啊,不知对错,啊~~~) 代码: #include "iostream" #include "string.h" #…

题意:给你一个矩阵M[i][j]表示i到j的距离 求最小生成树 思路:裸最小生成树 prime就可以了 最小生成树专题 AC代码: #include "iostream" #include "string.h" #include "stack" #include "queue" #include "string" #include "vector" #include "set&…

存图方式 最小生成树prime+队列优化 优化后时间复杂度是O(m*lgm) m为边数 优化后简直神速,应该说对于绝大多数的题目来说都够用了 具体有多快呢 请参照这篇博客:堆排序 Heapsort ///prime队列优化 #include "iostream" #include "string.h" #include "stack" #include "queue" #include "string" #…

poj1287 裸最小生成树 代码 #include "map" #include "queue" #include "math.h" #include "stdio.h" #include "string.h" #include "iostream" #include "algorithm" #define abs(x) x > 0 ? x : -x #def…

Co-prime Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3587    Accepted Submission(s): 1419 Problem Description Given a number N, you are asked to count the number of integers between A and B…

给定两个四位素数a  b,要求把a变换到b 变换的过程要保证  每次变换出来的数都是一个 四位素数,而且当前这步的变换所得的素数  与  前一步得到的素数  只能有一个位不同,而且每步得到的素数都不能重复. 求从a到b最少需要的变换次数.无法变换则输出Impossible   输入: 第一行 是一个数T 表示下面有T个测试数据 下面T行  每行两个数a b 解题思路:每次变换一次,个十百千,四个位置上的数每个从0-9循环一边一共需要4 * 10 = 40次循环  剪枝之后就没多少了 所以直接暴力…

Problem Description A ring is compose of n circles as shown in diagram. Put natural number 1, 2, ..., n into each circle separately, and the sum of numbers in two adjacent circles should be a prime. Note: the number of first circle should always be 1…

Problem Description A ring is compose of n circles as shown in diagram. Put natural number 1, 2, ..., n into each circle separately, and the sum of numbers in two adjacent circles should be a prime. Note: the number of first circle should always be 1…

/*本篇为转载,在此申明,具体就是先设定从2以后所有的数都为质数,定为质数的数的倍数则不是质数,慢慢排除后面的数*/ #include<iostream>#include<cstring>using namespace std;const int N = 1300000;//第10万个数为1299709int prime[N];bool notPrime[N]; int main(){  memset(prime,0,sizeof(prime)); memset(notPrime,…

1.Kruskal算法 图的存贮采用边集数组或邻接矩阵,权值相等的边在数组中排列次序可任意,边较多的不很实用,浪费时间,适合稀疏图.      方法:将图中边按其权值由小到大的次序顺序选取,若选边后不形成回路,则保留作为一条边,若形成回路则除去.依次选够(n-1)条边,即得最小生成树.(n为顶点数). Kruskal算法在图G=(V,E)上的运行时间取决于分离集合这一数据结构如何实现.采用在分离集合中描述的按行结合和通路压缩的启发式方法来实现分离集合森林的结构,这是从渐近意义上说,目前最快实现法…

题目链接: 传送门 Sum of Consecutive Prime Numbers Time Limit: 1000MS     Memory Limit: 65536K Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representations does a given positive intege…

题目链接: 传送门 Prime Land Time Limit: 1000MS     Memory Limit: 10000K Description Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,1,2,... denote the increasing…

题目链接 题意:输入一个数n (2 <= n <= 10000) 有多少种方案可以把n写成若干个连续素数之和 打出10000之内的素数表,然后再打出每个可能得到的和的方案数的表 #include <iostream> #include <cstring> #include <algorithm> #include <cstdio> using namespace std; ; ],total,flag[Max + ]; ]; //可以求出1000…

POJ 2739 Sum of Consecutive Prime Numbers Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu   Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representati…

http://poj.org/problem?id=1811 题意:求n最小素因子.(n<=2^54) #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <iostream> using namespace std; typedef long long ll; const ll lim=1e9; inline void C(…

简单的dfs,貌似这道题用暴力枚举就可以了,毕竟数据开的是比较小的. #include"iostream" #include"algorithm" #include"stdio.h" #include"string.h" #include"string" #include"vector" #include"cmath" #define mx 105 using nam…

Prime Query Time Limit: 1 Second Memory Limit: 196608 KB You are given a simple task. Given a sequence A[i] with N numbers. You have to perform Q operations on the given sequence. Here are the operations: A v l, add the value v to element with index…

By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13. What is the 10 001st prime number? 译文: 观察第一组质数可知,第6位质数为13,那么第10001位质数是多少呢? ============================ 第一次code: import java.util.ArrayList; import j…

Your task is simple:Find the first two primes above 1 million, whose separate digit sums are also prime.As example take 23, which is a prime whose digit sum, 5, is also prime.The solution is the concatination of the two numbers,Example: If the first…

Prime Test Time Limit: 6000MS   Memory Limit: 65536K Total Submissions: 29046   Accepted: 7342 Case Time Limit: 4000MS Description Given a big integer number, you are required to find out whether it's a prime number. Input The first line contains the…

Prime Distance Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12512   Accepted: 3340 Description The branch of mathematics called number theory is about properties of numbers. One of the areas that has captured the interest of number th…

  Prime Ring Problem  A ring is composed of n (even number) circles as shown in diagram. Put natural numbers into each circle separately, and the sum of numbers in two adjacent circles should be a prime. Note: the number of first circle should always…