SCU 4438 Censor(Hash)题解】的更多相关文章

 SCU 4438 Censor Time Limit:0MS     Memory Limit:0KB     64bit IO Format:%lld & %llu  Practice Description Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text pp. Her job is relatively simple -- just to find the…
Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text \(p\). Her job is relatively simple -- just to find the first occurence of sensitive word \(w\) and remove it. frog repeats over and over again. Help her do th…
题意:找出字符串p中的w串删除,反复操作,直到找不到w,输出这个串 思路:哈希处理前缀和,如果值相同就删掉. 代码: #include<iostream> #include<algorithm> #include<cstdio> #include<stdio.h> #include<string.h> #include<queue> #include<cmath> #include<map> #include&…
题意:给定一个模式串和文本,要求删除所有模式串.可能删除后会形成新的模式串,必须全部删除. 思路1:kmp算法求得失配数组,用一个match数组记录文本串中第i字符和未删除的字符能匹配模式串的长度.这样每次删除字符串之后就不用再匹配,直接查询match数组即可.用栈模拟,自己实现的栈可以加快速度. AC代码 #include <cstdio> #include <cmath> #include <cctype> #include <bitset> #incl…
传送门 Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text P. Her job is relatively simple -- just to find the first occurence of sensitive word w and remove it. frog repeats over and over again. Help her do the te…
Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text p . Her job is relatively simple -- just to find the first occurence of sensitive word w and remove it. frog repeats over and over again. Help her do the tedio…
frog is now a editor to censor so-called sensitive words (敏感词). She has a long text (p). Her job is relatively simple -- just to find the first occurence of sensitive word (w) and remove it. frog repeats over and over again. Help her do the tedious w…
Censor frog is now a editor to censor so-called sensitive words (敏感词). She has a long text pp. Her job is relatively simple -- just to find the first occurence of sensitive word ww and remove it. frog repeats over and over again. Help her do the tedi…
题意大概: 1.字符串hash不取模,自动溢出  构造数据卡这种hash 2.字符串hash取模1000000007,构造数据卡这种hash 题解传送门:VFleaKing http://vfleaking.blog.163.com/blog/static/1748076342013229102430789/…
Day 2 rank 11 100+35+30=165 本题是一道数论题,求ax+by=c的正整数对(x,y) x>=0并且y>=0 先说下gcd: 求a,b公约数gcd(a,b) 如gcd(4,6)=  2 辗转相除法 gcd(a,b)=gcd(b,a%b) 证明一下,令a=kb+r,那么r=a%b; 设d为(a,b)的一个任意公约数d,所以d|a且d|b 因为r=a-kb因为d|a且d|b,所以d|r注意到我们的d是任意选取的, 那么最大公约数是属于这个公因数集合里的所以gcd(a,b)=…