设$f[i][j][k]$表示从房间$j$的第$k$扇门进去探索不超过$i$步的情况. 对于$0$步的情况,可以用每个房间的度数来表示. 否则可以绕着那个房间走一圈,将所有情况依次hash来表示. 最后对于每个房间求出$f$的最小表示,即可完成hash. 时间复杂度$O(n^4)$. #include<cstdio> #include<vector> #include<algorithm> using namespace std; typedef unsigned lo…

Search GO 说明:输入题号直接进入相应题目,如需搜索含数字的题目,请在关键词前加单引号 Problem ID Title Source AC Submit Y 1000 A+B Problem 10983 18765 Y 1036 [ZJOI2008]树的统计Count 5293 13132 Y 1588 [HNOI2002]营业额统计 5056 13607 1001 [BeiJing2006]狼抓兔子 4526 18386 Y 2002 [Hnoi2010]Bounce 弹飞绵羊 43…

Sept. 10, 2015 Study again the back tracking algorithm using recursive solution, rat in maze, a classical problem. Made a few of mistakes through the practice, one is how to use two dimension array, another one is that "not all return path returns va…

废话不多说,大名鼎鼎的Lenstra-Lenstra-Lovasz(LLL) 算法.实现参考论文:Factoring Polynomials with Rational Coefficients, 作者 A.K. Lenstra, H.W. Lenstra, Jr. and L. Lovasz. /* File : LLL Lattice Reduction Matlab mex interface * Description : do Lattice Reduction in the Real…

http://www.lightoj.com/volume_showproblem.php?problem=1027 You are in a maze; seeing n doors in front of you in beginning. You can choose any door you like. The probability for choosing a door is equal for all doors. If you choose the ith door, it ca…

10. Dimensionality Reduction Content  10. Dimensionality Reduction 10.1 Motivation 10.1.1 Motivation one: Data Compression 10.2.2 Motivation two: Visualization 10.2 Principal Component Analysis 10.2.1 Problem formulation 10.2.2 Principal Component An…

转自: http://hackecho.com/2013/04/cuda-parallel-reduction/ Parallel Reduction是NVIDIA-CUDA自带的例子,也几乎是所有CUDA学习者的的必看算法.在这个算法的优化中,Mark Harris为我们实现了7种不同的优化版本,将Bandwidth几乎提高到了峰值.相信我们通过仔细研读这个过程,一定能对CUDA程序的优化有更加深刻的认识.下面我们来一一细看这几种优化方案,数据和思想均摘录自官方SDK中Samples的算法说明…

1204.   Maze Traversal A common problem in artificial intelligence is negotiation of a maze. A maze has corridors and walls. The robot can proceed along corridors, but cannot go through walls. Input For this problem, you will input the dimensions of…

/*这道题我原本是将斜线迷宫扩大为原来的两倍,但是在这种情况下对于在斜的方向上的搜索会变的较容易出错,所以参考了别人的思路后将迷宫扩展为原来的3倍,这样就变成一般的迷宫问题了*/ #include"iostream" #include"stdio.h" #include"algorithm" #include"cmath" #include"string.h" #include"ctype.h&q…

Zhuge Liang's Stone Sentinel Maze Time Limit: 10000/4000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 385    Accepted Submission(s): 106 Problem Description Zhuge Liang was a chancellor of the state of Shu Han dur…