给定两个整数 L 和 R ,找到闭区间 [L, R] 范围内,计算置位位数为质数的整数个数. (注意,计算置位代表二进制表示中1的个数.例如 21 的二进制表示 10101 有 3 个计算置位.还有,1 不是质数.) 示例 1: 输入: L = 6, R = 10 输出: 4 解释: 6 -> 110 (2 个计算置位,2 是质数) 7 -> 111 (3 个计算置位,3 是质数) 9 -> 1001 (2 个计算置位,2 是质数) 10-> 1010 (2 个计算置位,2 是质数…
Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written in bin…
[抄题]: Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written…
problem 762. Prime Number of Set Bits in Binary Representation solution1: class Solution { public: int countPrimeSetBits(int L, int R) { int res = 0; int bits = 0; for(int i=L; i<=R; i++) { bits = countBits(i); if(isPrime(bits) && bits!=1 ) res…
Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written in bin…
题目要求 Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written i…
Given two integers L and R, find the count of numbers in the range [L, R](inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written in bina…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 遍历数字+质数判断 日期 题目地址:https://leetcode.com/problems/prime-number-of-set-bits-in-binary-representation/description/ 题目描述 Given two integers L and R, find the count of numbers in the…
思路:动态规划.注意1024*1024>10^6,所以质素范围是(0,23). class Solution { public int countPrimeSetBits(int L, int R) { Set<Integer> prime = new HashSet<Integer>(Arrays.asList(2,3,5,7,11,13,17,19,23)); int[] count = new int[1+R]; int res = 0; for(int i = 1;…
这是悦乐书的第311次更新,第332篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第180题(顺位题号是762).给定两个正整数L和R,在[L,R]范围内,计算每个整数的二进制数中1的个数,判断1的个数是否是一个素数.例如,21的二进制数是10101,其中1的个数有3个,3是一个素数.例如: 输入:L = 6,R = 10 输出:4 说明: 6 --> 110(2个1,2是素数) 7 --> 111(3个1,3是素数) 9 --> 1001(2个1,2是素数…