LeetCode 691. Stickers to Spell Word】的更多相关文章

原题链接在这里:https://leetcode.com/problems/stickers-to-spell-word/ 题目: We are given N different types of stickers. Each sticker has a lowercase English word on it. You would like to spell out the given target string by cutting individual letters from your…
We are given N different types of stickers. Each sticker has a lowercase English word on it. You would like to spell out the given target string by cutting individual letters from your collection of stickers and rearranging them. You can use each sti…
We are given N different types of stickers. Each sticker has a lowercase English word on it. You would like to spell out the given target string by cutting individual letters from your collection of stickers and rearranging them. You can use each sti…
We are given N different types of stickers. Each sticker has a lowercase English word on it. You would like to spell out the given targetstring by cutting individual letters from your collection of stickers and rearranging them. You can use each stic…
We are given N different types of stickers. Each sticker has a lowercase English word on it. You would like to spell out the given target string by cutting individual letters from your collection of stickers and rearranging them. You can use each sti…
Design a data structure that supports the following two operations: void addWord(word)bool search(word) search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter.…
leetcode: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non…
https://leetcode.com/problems/maximum-product-of-word-lengths/ Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lo…
https://leetcode.com/problems/add-and-search-word-data-structure-design/ 本题是在Trie树进行dfs+backtracking操作. Trie树模板代码见:http://www.cnblogs.com/fu11211129/p/4952255.html 题目介绍: Design a data structure that supports the following two operations: void addWord…
Given two words (start and end), and a dictionary, find all shortest transformation sequence(s) from start to end, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For example, Given:start = "hit…
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…
Design a data structure that supports the following two operations: void addWord(word) bool search(word) search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter…
691. 贴纸拼词 我们给出了 N 种不同类型的贴纸.每个贴纸上都有一个小写的英文单词. 你希望从自己的贴纸集合中裁剪单个字母并重新排列它们,从而拼写出给定的目标字符串 target. 如果你愿意的话,你可以不止一次地使用每一张贴纸,而且每一张贴纸的数量都是无限的. 拼出目标 target 所需的最小贴纸数量是多少?如果任务不可能,则返回 -1. 示例 1: 输入: ["with", "example", "science"], "th…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/shortest-completing-word/description/ 题目描述 Find the minimum length word from a given dictionary words, which has all the letters from the…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 正则+统计 日期 题目地址:https://leetcode.com/problems/most-common-word/description/ 题目描述 Given a paragraph and a list of banned words, return the most frequent word that is not in the li…
题目简述 Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spac…
https://leetcode.com/problems/length-of-last-word/ int lengthOfLastWord(char* s) { int ans = 0; int fans = 0; for(int i = 0;s[i];i++){ if (s[i] ==' '){fans = ans;ans = 0;while(s[i + 1] == ' '){i++;}} else ans++; } return ans?ans:fans; }…
Given a 2D board and a word, find if the word exists in the grid. The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be us…
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…
Design a data structure that supports the following two operations: void addWord(word) bool search(word) search(word) can search a literal word or a regular expression string containing only letters a-z or .. A . means it can represent any one letter…
题目描述: Given a string array words, find the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. You may assume that each word will contain only lower case letters. If no such two words exist, return 0. E…
题目描述: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-spa…
题目链接 写一个数据结构, 支持两种操作. 加入一个字符串, 查找一个字符串是否存在.查找的时候, '.'可以代表任意一个字符. 显然是Trie树, 添加就是正常的添加, 查找的时候只要dfs查找就可以. 具体dfs方法看代码. struct node { node *next[]; int idEnd; node() { memset(next, NULL, sizeof(next)); idEnd = ; } }; class WordDictionary { public: // Adds…
题目: Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space…
这是悦乐书的第309次更新,第330篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第178题(顺位题号是748).从给定的字典单词中查找最小长度单词,其中包含字符串licensePlate中的所有字母.据说这样的单词可以完成给定的字符串licensePlate.在这里,对于字母我们忽略大小写.例如,licensePlate上的"P"仍与单词上的"p"匹配.答案肯定存在.如果有多个答案,则返回数组中首先出现的答案.licensePlate…
Given a 2D board and a word, find if the word exists in the grid.The word can be constructed from letters of sequentially adjacent cell, where "adjacent" cells are those horizontally or vertically neighboring. The same letter cell may not be use…
Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…
Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space cha…
[ 问题: ] Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. 给你一个字符串,设法获取它最后一个单词的长度.假设这个单词不存在,则返回0. [ 分析 : ] A word is defined…