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73. Set Matrix Zeroes - 先扫描第一行第一列,如果有0,则将各自的flag设置为true- 然后扫描除去第一行第一列的整个数组,如果有0,则将对应的第一行和第一列的数字赋0- 再次遍历除去第一行第一列的整个数组,如果对应的第一行和第一列的数字有一个为0,则将当前值赋0- 最后根据第一行第一列的flag来更新第一行第一列 class Solution { public void setZeroes(int[][] matrix) { boolean isZeroCol = f…
Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed). E…
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突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…
1. Array 基础 27 Remove Element 26 Remove Duplicates from Sorted Array 80 Remove Duplicates from Sorted Array II 277 Find the Celebrity 189 Rotate Array 41 First Missing Positive 299 Bulls and Cows 134 Gas Station 118 Pascal's Triangle 很少考 119 Pascal's…
coreJava部分 7 1.面向对象的特征有哪些方面? 7 2.作用域public,private,protected,以及不写时的区别? 7 3.String 是最基本的数据类型吗? 7 4.float 型float f=3.4是否正确? 7 5.语句float f=1.3:编译能否通过? 7 6.short s1 = 1; s1 = s1 + 1;有什么错? 7 7.Java 有没有goto? 7 8.int 和Integer 有什么区别? 7 9.&和&&的区别? 8 10…
[11] Container With Most Water [Medium] O(n^2)的暴力解法直接TLE. 正确的解法是Two Pointers. O(n)的复杂度.保持两个指针i,j:分别指向长度数组的首尾.如果ai 小于aj,则移动i向后(i++).反之,移动j向前(j--).如果当前的area大于了所记录的area,替换之.这个想法的基础是,如果i的长度小于j,无论如何移动j,短板在i,不可能找到比当前记录的area更大的值了,只能通过移动i来找到新的可能的更大面积. class…
在此记录Tenseal的学习笔记 介绍 在张量上进行同态计算的库,是对Seal的python版实现,给开发者提供简单的python接口,无需深究底层密码实现. 当前最新版本:3.11 位置:A library for doing homomorphic encryption operations on tensors 具备以下特点: BFV方案的加解密(整数) CKKS方案的加解密(浮点数) 密文-密文.密文-明文的加法和乘法运算(同态计算) 点积和矩阵乘法 将Seal封装为tenseal.se…
Leetcode之深度优先搜索(DFS)专题-329. 矩阵中的最长递增路径(Longest Increasing Path in a Matrix) 深度优先搜索的解题详细介绍,点击 给定一个整数矩阵,找出最长递增路径的长度. 对于每个单元格,你可以往上,下,左,右四个方向移动. 你不能在对角线方向上移动或移动到边界外(即不允许环绕). 示例 1: 输入: nums = [ [9,9,4], [6,6,8], [2,1,1] ] 输出: 4 解释: 最长递增路径为 [1, 2, 6, 9].…
题目 Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed)…
题目: Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. Follow up: Did you use extra space? A straight forward solution using O(mn) space is probably a bad idea. A simple improvement uses O(m + n) space, but…
原题地址 用矩形的第一行和第一列充当mask 代码: void setZeroes(vector<vector<int> > &matrix) { ].empty()) return; bool firstRow = false; bool firstCol = false; int m = matrix.size(); ].size(); ; i < m; i++) ] == ) { firstCol = true; break; } ; j < n; j++…
https://leetcode.com/problems/longest-increasing-path-in-a-matrix/ Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally o…
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. Follow up: Did you use extra space?A straight forward solution using O(mn) space is probably a bad idea.A simple improvement uses O(m + n) space, but still…
最后更新 三刷? 找矩阵里的最长路径. 看起来是DFS,实际上也就是.但是如果从每个点都进行一次DFS然后保留最大的话,会超时. 这里需要结合DP,dp[i][j]表示以此点开始的最长路径,这样每次碰到的时候,如果已经算过,可以直接调取这个值. 用空间交换了部分时间. 写的时候我吸取教训,把边界判断放在DFS的开始.. Time Complexity: 不会算.. O(4mn)?因为只能单方向= =,每个点往一个方向延伸,就不可能回来. Space : O(m*n) public class S…
给定一个矩阵,把零值所在的行和列都置为零.例如: 1 2 3 1 3 1 1 1 操作之后变为 1 3 0 0 0 1 1 方法1: 赋值另存一个m*n的矩阵,在原矩阵为零的值相应置新的矩阵行和列为零.额外空间为O(m*n). 方法2: 两个数组,bool[m] 和 bool[n] 分别存某行有零,后者某列有零.之后根据数组值将原矩阵相应位置置零.额外空间O(m + n). class Solution { public: void setZeroes(vector<vector<int>…
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. click to show follow up. Follow up: Did you use extra space?A straight forward solution using O(mn) space is probably a bad idea.A simple improvement uses O…
题目: Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. Follow up: Did you use extra space? A straight forward solution using O(mn) space is probably a bad idea. A simple improvement uses O(m + n) space, but…
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. click to show follow up. Follow up: Did you use extra space?A straight forward solution using O(mn) space is probably a bad idea.A simple improvement uses O…
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. 重点是空间复杂度限制为常数. 人家想法: 用 matrix 的第0行和第0列的元素分别记录所对应的行和列是否有0. A[0][0]比较特殊,我们只让它记录第0行的情况,声明另一变量col0记录第0列的情况. 我的实现代码较长,但思路表达的相当清楚.人家也有贼短的代码,人家很牛逼. 算法分两大阶段(细分为 8 s…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. (二)解题 题目大意:给定一个M*N的数组,如果(i,j)为0,则将第i行第j列全部元素置为0. 这道题目意思很简单,如果考虑…
[抄题]: Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in-place. Example 1: Input: [   [1,1,1],   [1,0,1],   [1,1,1] ] Output: [   [1,0,1],   [0,0,0],   [1,0,1] ] [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: [奇葩输出条件]: [奇葩…
Matrix Time Limit: 2 Seconds      Memory Limit: 65536 KB Given an n*n matrix A, whose entries Ai,j are integer numbers ( 0 <= i < n, 0 <= j < n ). An operation SHIFT at row i ( 0 <= i < n ) will move the integers in the row one position…
Given an integer matrix, find the length of the longest increasing path. From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed). E…
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. Follow up: Did you use extra space? A straight forward solution using O(mn) space is probably a bad idea. A simple improvement uses O(m + n) space, but stil…
Set Matrix Zeroes Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. click to show follow up. Follow up: Did you use extra space?A straight forward solution using O(mn) space is probably a bad idea.A simple…
题目:矩阵置0 难度:Easy 题目内容: Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in-place. 翻译: 给定一个m x n矩阵,如果一个元素是0,就把它的整行和列设为0. 要求:就地置0. Example 1: Input: [   [1,1,1],   [1,0,1],   [1,1,1] ] Output: [   [1,0,1],   [0,0,0],  …
题目 Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place. click to show follow up. Follow up: Did you use extra space? A straight forward solution using O(mn) space is probably a bad idea. A simple improvement u…
问题描述:将二维数组中值为0的元素,所在行或者列全set为0:https://leetcode.com/problems/set-matrix-zeroes/ 问题分析:题中要求用 constant space 的辅助空间.自然想到位优化.一个int可以存储31个元素的信息.这里刚好用到了字符串论文里面常用的优化处理方法.类似桶分的思想.好吧,这么看来这长时间的论文没白看. 附上代码: void setZeroes(vector<vector<int>>& matrix)…
Given an integer matrix, find the length of the longest increasing path.From each cell, you can either move to four directions: left, right, up or down. You may NOT move diagonally or move outside of the boundary (i.e. wrap-around is not allowed).Exa…