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题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=4800 Problem Description A role-playing game (RPG and sometimes roleplaying game) is a game in which players assume the roles of characters in a fictional setting. Players take responsibility for acting…
UVALive - 3942 Remember the Word Neal is very curious about combinatorial problems, and now here comes a problem about words. Know- ing that Ray has a photographic memory and this may not trouble him, Neal gives it to Jiejie. Since Jiejie can’t remem…
A Scheduling Problem   Description There is a set of jobs, say x1, x2,..., xn <tex2html_verbatim_mark>, to be scheduled. Each job needs one day to complete. Your task is to schedule the jobs so that they can be nished in a minimum number of days. Th…
Tree Maker Problem Description Tree Lover loves trees crazily. One day he invents an interesting game which is named Tree Maker. In this game, all trees are binary trees. Initially, there is a tree with only one vertex and a cursor on it. Tree Lover…
3942 - Remember the Word Neal is very curious about combinatorial problems, and now here comes a problem about words. Knowing that Ray has a photographic memory and this may not trouble him, Neal gives it to Jiejie. Since Jiejie can't remember number…
T3:BFS 回看了一下Day1的T3...感觉裸裸的BFS,自己当时居然没有看出来... 同时用上升和下降两种状态bfs即可 这一题还要注意一个细节的地方,就是题目要求的是求往返的最优解 k=min(d[上升],d[下降]); ans=min(2*k+1,d1[]+d2[]); 输出ans..这个地方需要理解: 以及如果这个点在边缘地区(边界) 且这个点的高度为0 那么就不需要转化 其余的照bfs模板打即可: //刚开始以为是把每一个点都bfs一遍,看了标程之后发现有一个优很多的解法: 把出发…
Given a positive integer n, return the number of all possible attendance records with length n, which will be regarded as rewardable. The answer may be very large, return it after mod 109 + 7. A student attendance record is a string that only contain…
前篇戳:dp入门——由分杆问题认识动态规划 导语 刷过一些算法题,就会十分珍惜“方法论”这种东西.Leetcode上只有题目.讨论和答案,没有方法论.往往答案看起来十分切中要害,但是从看题目到得到思路的那一段,就是绕不过去.楼主有段时间曾把这个过程归结于智商和灵感的结合,直到有天为了搞懂Leetcode上一位老兄的题型总结,花两天时间学习了回溯法,突然有种惊为天人的感觉——原来真正掌握一个算法是应该触类旁通的,而不是将题中一个细节换掉就又成了新题…… 掌握方法论绝对是一种很爽的感觉.看起来好像很…
接着第四课的内容,加入部分第五课的内容,主要介绍树形dp和LRU 第一题: 给定一棵二叉树的头节点head,请返回最大搜索二叉子树的大小 二叉树的套路 统一处理逻辑:假设以每个节点为头的这棵树,他的最大搜索二叉子树是什么.答案一定在其中 第一步,列出可能性(最难部分) 1.可能来自左子树上的某课子树 2.可能来自右子树上的某课子树 3.整颗都是(左右子树都是搜索二叉树并且左子树最大小于该节点,右子树最小大于该节点) 第二步,收集信息: 1.左树最大搜索子树大小 2.右树最大搜索子树大小 3.左树…
A.GPA(HDU4802): 给你一些字符串对应的权重,求加权平均,如果是N,P不计入统计 GPA Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1193    Accepted Submission(s): 743 Problem Description In college, a student may take several…