题意: 给定两个32位的整数 N 和 M,以及表示比特位置的 i 与 j .编写一个方法,将 M 插入 N,使得 M 从 N 的第 j 位开始,到第 i 位结束.假定从 j 位到 i 位足以容纳M. 输入:N = 10000101000,M = 10011,i = 2, j = 6 输出:N = 10001001100 解题思路 :  根据题意,我们将问题解决分为三个步骤: (1)将 N 中从 j 到 i 之间的位清零: (2)对 M 进行移位操作,M << i (3)合并 M 与 N . 为…

Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路: 这个题是Single Number的进阶版,如果其他的数都出现两次而…

原题地址https://leetcode.com/problems/single-number-ii/ 题目描述Given an array of integers, every element appears three times except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现三次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime co…

Single Number II Given an array of integers, every element appears threetimes except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解法一:开辟map记录次数 class So…

Single Number II Given 3*n + 1 numbers, every numbers occurs triple times except one, find it. Example Given [1,1,2,3,3,3,2,2,4,1] return 4 Challenge One-pass, constant extra space. 统计每一位上的1出现的次数,然后模3 , 题目上的3 * n + 1给了提示,然后又做过一题2 * n + 1的位操作. public…

题目描述: Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Single Number II Given…

LintCode 83. Single Number II (Medium) LeetCode 137. Single Number II (Medium) 以下算法的复杂度都是: 时间复杂度: O(n) 空间复杂度: O(1) 解法1. 32个计数器 最简单的思路是用32个计数器, 满3复位0. class Solution { public: int singleNumberII(vector<int> &A) { int cnt[32] = {0}; int res = 0; f…

Single Number Total Accepted: 103745 Total Submissions: 218647 Difficulty: Medium Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you imp…

问题来源:Single Number II 问题描述:给定一个整数数组,除了一个整数出现一次之外,其余的每一个整数均出现三次,请找出这个出现一次的整数. 大家可能很熟悉另一个题目(Single Number):除了一个数出现一次之外,其余的均出现两次,找到出现一次的数.该问题很简单,大家肯定都知道解法:将所有的数异或,最后的结果即是出现一次的数.用到的知识是A^A=0,两个相同的数异或变为0,然后0^B=B,这样即可找到出现一次的数. 新问题有了变化,出现两次变成出现三次,整个问题的解法就不一样…

题目描述: 给定一个数组,里面除了一个数字,其他的都出现三次.求出这个数字 原文描述: Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra m…