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Given an array of integers, return indices of the two numbers such that they add up to a specific target. You may assume that each input would have exactly one solution, and you may not use the same element twice. Example: Given nums = [2, 7, 11, 15]…
You are given a binary tree in which each node contains an integer value. Find the number of paths that sum to a given value. The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to…
JAVA7 Java7的ConcurrentHashMap里有多把锁,每一把锁用于其中一部分数据,那么当多线程访问容器里不同数据段的数据时,线程间就不会存在锁竞争,从而可以有效的提高并发访问效率呢.这就是“锁分离”技术. ConcurrentHashMap是由Segment数组结构和HashEntry数组结构组成.Segment是一种可重入锁(继承了ReentrantLock),在ConcurrentHashMap里扮演锁的角色,HashEntry则用于存储键值对数据. ConcurrentHa…
val conf = HBaseConfiguration.create() conf.addResource(new Path("/opt/cloudera/parcels/CDH-5.4.4-1.cdh5.4.4.p0.4/lib/hbase/conf/hbase-site.xml")) conf.addResource(new Path("/opt/cloudera/parcels/CDH-5.4.4-1.cdh5.4.4.p0.4/lib/hadoop/etc/had…
[leetcode]1. Two Sum两数之和 Two Pointers, HashMap Easy [leetcode]2. Add Two Numbers两数相加 Math, LinkedList Medium [leetcode]3. Longest Substring Without Repeating Characters无重复字母的最长子串 Sliding Window Medium [leetcode]4. Median of Two Sorted Arrays俩有序数组的中位数…
一.选择题汇总,具体的记不住啦.. 1.计网:ip的网络前缀.SNMP(报文组成):http://blog.csdn.net/shanzhizi/article/details/11606767 参考这个博客 TCP协议 2.数据库连接查询.全文索引:select * from product where match(detail) fulltext('jyc') 3.PAD图.N-S图 4.hash映射. 5.CSS中透明的部分 6.DMA.中断 7.线性窥孔 8.编译原理的表达式 9.and…
package DecisionTree; import java.io.*; import java.util.*; public class ID3 { //节点类 public class DTNode { private String attribute; private HashMap<String, DTNode> children = new HashMap<String, DTNode>(); public String getAttribute() { retur…
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Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero. Note: The solution set must not contain duplicate triplets. For example, given array S = [-1,…
leetcode 第五天 2018年1月6日 22.(566) Reshape the Matrix JAVA class Solution { public int[][] matrixReshape(int[][] nums, int r, int c) { int[][] newNums = new int[r][c]; int size = nums.length*nums[0].length; if(r*c != size) return nums; for(int i=0;i<siz…