poj 2029 二维树状数组】的更多相关文章

思路:简单树状数组 #include<map> #include<set> #include<cmath> #include<queue> #include<cstdio> #include<vector> #include<string> #include<cstdlib> #include<cstring> #include<iostream> #include<algorit…
Mobile phones Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 18489   Accepted: 8558 Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The…
思路:直接用long long 保存会WA.用下高精度加法就行了. #include<map> #include<set> #include<cmath> #include<queue> #include<cstdio> #include<vector> #include<string> #include<iomanip> #include<cstdlib> #include<cstring&…
Matrix Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 33682   Accepted: 12194 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (…
Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The squares form an S * S matrix with the rows and columns numbered from 0 to S-1. Each square contains a base sta…
Get Many Persimmon Trees Time Limit:1000MS    Memory Limit:30000KB    64bit IO Format:%I64d & %I64u SubmitStatusPracticePOJ 2029 Description Seiji Hayashi had been a professor of the Nisshinkan Samurai School in the domain of Aizu for a long time in…
题目链接 题意 : 给你每个柿子树的位置,给你已知长宽的矩形,让这个矩形包含最多的柿子树.输出数目 思路 :数据不是很大,暴力一下就行,也可以用二维树状数组来做. #include <stdio.h> #include <string.h> #include <iostream> using namespace std ; ][] ; int main() { int N ,S,T ,W,H; while(scanf("%d",&N) !=…
<题目链接> 题目大意: 给你一个H*W的矩阵,再告诉你有n个坐标有点,问你一个w*h的小矩阵最多能够包括多少个点. 解题分析:二维树状数组模板题. #include <cstdio> #include <cstring> #include <algorithm> using namespace std; +; int tr[M][M]; int n,W,H,w,h; int lowbit(int x){return x&(-x);} void ad…
思路: 大力出奇迹,先用二维树状数组存,然后暴力枚举 算某个矩形区域的值的示意图如下,代码在下面慢慢找... 代码: #include<cstdio> #include<map> #include<cstring> #include<algorithm> #define ll long long using namespace std; const int N = 1030+5; int bit[N][N],n,m; int lowbit(int x){ r…
Mobile phones Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 14489   Accepted: 6735 Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The…