称号:计算一个数字是不17倍数. 说明:串,睑板. 简单的问题,直接推论可以是. 设定 n = 10a + d:(0 ≤ d ≤ 9) a - 5d = 51a - 5n,假设n被17整除,这个数必定也被17整除. 说明:题目给了个结论,不须要用,直接%17推断余数就可以. #include <iostream> #include <cstdlib> #include <cstring> #include <cstdio> using namespace s…

 Tree Recovery  Little Valentine liked playing with binary trees very much. Her favoritegame was constructingrandomly looking binary trees with capital letters in the nodes. This is an example of one of her creations: D / \ / \ B E / \ \ / \ \ A C G…

 Parentheses Balance  You are given a string consisting of parentheses () and []. Astring of this type is said to be correct: (a) if it is the empty string (b) if A and B are correct, AB is correct, (c) if A is correct, (A ) and [A ] is correct. Writ…

题号:a001: 哈囉 背景知识:输出语句,while not eof 题号:a002: 簡易加法 背景知识:输出语句,while not eof,加法运算 题号:a003: 兩光法師占卜術 背景知识:while not eof,分支语句,求余 PS:%表示求余 题号:a004: 文文的求婚 背景知识:while not eof,分支语句,判断闰年 题号:a005: Eva 的回家作業 背景知识:循环,if语句,等比数列,等差数列,输出语句 题号:a006: 一元二次方程式 背景知识:if语句的…

题意: 给定m个1位数字,要求用这些数字组成n的倍数的最小数字,如果无法组成就输出0 分析: BFS,由于n最大5000,余数最多5000,利用余数去判重,并记录下路径即可 代码: #include <iostream> #include <cstring> #include <cstdio> #include <algorithm> #include <vector> using namespace std; const int maxn=50…

UVA - 11134 Fabled Rooks We would like to place n rooks, 1 ≤ n ≤ 5000, on a n × n board subject to the following restrictions The i-th rook can only be placed within the rectan- gle given by its left-upper corner (xli,yli) and its right- lower corner…

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=83 147 - Dollars Time limit: 3.000 seconds Dollars New Zealand currency consists of $100, $50, $20, $10, and $5 notes and $2, $1, 50c, 20c, 10c and…

#include<bits/stdc++.h> using namespace std; int main() { unsigned ]; memset(dp,,sizeof(dp)); dp[]=; ;i<=;i++) ;j++) dp[j]=dp[j]+dp[j-i]; int n; while((scanf("%d",&n))!=EOF) { printf("%I64d\n",dp[n]); } ; ; } 这两道题基本思路是一样的,…

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UVA - 1025 A Spy in the Metro Secret agent Maria was sent to Algorithms City to carry out an especially dangerous mission. After several thrilling events we find her in the first station of Algorithms City Metro, examining the time table. The Algorit…

Mysql 5.7.17发布了,主要修复: Changes in MySQL 5.7.17 (2016-12-12, General Availability) Compilation Notes MySQL Enterprise Notes Packaging Notes Security Notes Test Suite Notes Functionality Added or Changed Bugs Fixed Compilation Notes For GCC versions hig…

本文转自:http://jinaldesai.net/stop-sharing-session-state-between-multiple-tabs-of-browser/ Scenario: By default all browsers share session state between multiple tabs. So if you logged into one tab with particular site and open internal link of the same…

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211 - The Domino Effect Time limit: 3.000 seconds A standard set of Double Six dominoes contains 28 pieces (called bones) each displaying two numbersfrom 0 (blank) to 6 using dice-like pips. The 28 bones, which are unique, consist of the followingcom…

C. Balance 题目链接 http://codeforces.com/contest/17/problem/C 题面 Nick likes strings very much, he likes to rotate them, sort them, rearrange characters within a string... Once he wrote a random string of characters a, b, c on a piece of paper and began…

题目来源:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=39  Stacking Boxes  Background Some concepts in Mathematics and Computer Science are simple in one or two dimensions but become…

题目来源:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=3&page=show_problem&problem=36  The 3n + 1 problem  Background Problems in Computer Science are often classified as belonging to a certain class of problem…

问题来源:刘汝佳<算法竞赛入门经典--训练指南> P81: 问题描述:你的任务是在n*n(1<=n<=5000)的棋盘上放n辆车,使得任意两辆车不相互攻击,且第i辆车在一个给定的矩形R之内. 问题分析:1.题中最关键的一点是每辆车的x坐标和y坐标可以分开考虑(他们互不影响),不然会变得很复杂,则题目变成两次区间选点问题:使得每辆车在给定的范围内选一个点,任何两辆车不能选同一个点.  2.本题另外一个关键点是贪心法的选择,贪心方法:对所有点的区间,按右端点从小到大排序:每次在一个区间…

说明:关于Uva的题目,可以在vjudge上做的,不用到Uva(那个极其慢的)网站去做. 最小瓶颈路:找u到v的一条路径满足最大边权值尽量小 先求最小生成树,然后u到v的路径在树上是唯一的,答案就是这条路径. Uva 534 Frogger Time Limit: 3000MS 64bit IO Format: %lld & %llu Description Freddy Frog is sitting on a stone in the middle of a lake. Suddenly h…

章节概述: 本章节将分析SCSI与iSCSI技术结构的不同,了解iSCSI技术的优势.SAN存储网络技术结构以及iSCSI HBA卡的作用. 完整演示部署iSCSI target服务程序的方法流程:创建RAID阵列(5)后使用targetcli命令发布到iSCSI存储目录并创建ACL列表. 配置使用iSCSI initiator服务程序发现.连接并使用iSCSI存储设备,最后编辑fstab文件将存储设备设置为开机启动. 本章目录结构 17.1 网络存储技术 17.2 部署iSCSI存储 17.2…

1.LA 5694 Adding New Machine 关键词:数据结构,线段树,扫描线(FIFO) #include <algorithm> #include <cstdio> #include <cstring> #include <string> #include <queue> #include <map> #include <set> #include <ctime> #include <cm…

Scheduling Lectures Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 607 Appoint description:  System Crawler  (2015-08-26) Description   You are teaching a course and must cover n ( ) topics. The leng…

十五 Twenty Questions Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVA 1252 Appoint description:  System Crawler  (2015-08-25) Description   Consider a closed world and a set of features that are defined…

[2015-04-16 17:42:04 - Dex Loader] Unable to execute dex: Multiple dex files define Lcom/gl/softphone/AudioInfo; [2015-04-16 17:42:04 - YunzhixunApp] Conversion to Dalvik format failed: Unable to execute dex: Multiple dex files define Lcom/gl/softpho…

遇到报错: [2014-02-13 17:27:03 - Dex Loader] Unable to execute dex: Multiple dex files define Lcom/kkdiangame/UI/res/FileUtils; [2014-02-13 17:27:03 - MiniBrowser] Conversion to Dalvik format failed: Unable to execute dex: Multiple dex files define Lcom/…

17: LCS Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 184  Solved: 43[Submit][Status][Web Board] Description Giving two strings consists of only lowercase letters, find the LCS(Longest Common Subsequence) whose all partition are not less than k in l…

// The 3n+1 problem (3n+1 问题) // PC/UVa IDs: 110101/100, Popularity: A, Success rate: low Level: 1 // Verdict: Accepted // Submission Date: 2011-05-22 // UVa Run Time: 0.032s // // 版权所有(C)2011,邱秋.metaphysis # yeah dot net. // // [问题描述] // 考虑如下的序列生成算法…

UVa 10006 - Carmichael Numbers An important topic nowadays in computer science is cryptography. Some people even think that cryptography is the only important field in computer science, and that life would not matter at all without cryptography. Alvar…

 A Puzzling Problem  The goal of this problem is to write a program which will take from 1 to 5 puzzle pieces such as those shown below and arrange them, if possible, to form a square. An example set of pieces is shown here. The pieces cannot be rota…

题意: long long H(int n){ long long res = 0; for( int i = 1; i <= n; i=i+1 ){ res = (res + n/i); } return res;} 求这样一个函数的值. 分析: 这个题很像我做莫比乌斯反演时的一个分块加速的优化. 注意到n/i的整数部分,有许多重复的数.具体一点,对于某一个i,在区间[i, n / (n / i)]中n/i的值是一样的. 例如在[17, 20]中的i,100/i的值都是5. #include…