UVA The Sultan's Successors】的更多相关文章

题目例如以下: The Sultan's Successors  The Sultan of Nubia has no children, so she has decided that thecountry will be split into up to k separate parts on her death andeach part will be inherited by whoever performs best at some test. Itis possible for an…
这道题是典型的八皇后问题,刘汝佳书上有具体的解说. 代码的实现例如以下: #include <stdio.h> #include <string.h> #include <stdlib.h> int vis[100][100];//刚開始wrong的原因就是这里数组开小了,开了[8][8],以为可以.后来看到[cur-i+8]意识到可能数组开小了.改大之后AC. int a[8][8]; int C[10]; int max_,tot; void search_(int…
UVA 816 - Abbott's Revenge option=com_onlinejudge&Itemid=8&page=show_problem&category=599&problem=757&mosmsg=Submission+received+with+ID+14332151" target="_blank" style="">题目链接 题意:一个迷宫,每一个点限制了从哪一方向来的.仅仅能往左右前…
题目链接:uva 11825 题意: 你是一个黑客,侵入了n台计算机(每台计算机有同样的n种服务),对每台计算机,你能够选择终止一项服务,则他与其相邻的这项服务都终止.你的目标是让很多其它的服务瘫痪(没有计算机有该项服务). 思路:(见大白70页,我的方程与大白不同) 把n个集合P1.P2.Pn分成尽量多的组,使得每组中全部集合的并集等于全集,这里的集合Pi是计算机i及其相邻计算机的集合,用cover[i]表示若干Pi的集合S中全部集合的并集,dp[s]表示子集s最多能够分成多少组,则 假设co…
UVA 10831 - Gerg's Cake 题目链接 题意:说白了就是给定a, p.问有没有存在x^2 % p = a的解 思路:求出勒让德标记.推断假设大于等于0,就是有解,小于0无解 代码: #include <stdio.h> #include <string.h> long long a, p; long long pow_mod(long long x, long long k, long long mod) { long long ans = 1; while (k…
UVA 12103 - Leonardo's Notebook 题目链接 题意:给定一个字母置换B.求是否存在A使得A^2=B 思路:随意一个长为 L 的置换的k次幂,会把自己分裂成gcd(L,k) 分, 而且每一份的长度都为 L / gcd(l,k).因此平方对于奇数长度不变,偶数则会分裂成两份长度同样的循环,因此假设B中偶数长度的循环个数不为偶数必定不存在A了 代码: #include <stdio.h> #include <string.h> const int N = 30…
UVA 11774 - Doom's Day 题目链接 题意:给定一个3^n*3^m的矩阵,要求每次按行优先取出,按列优先放回,问几次能回复原状 思路:没想到怎么推理,找规律答案是(n + m) / gcd(n, m),在topcoder上看到一个证明,例如以下: We can associate at each cell a base 3-number, the log3(R) most significant digits is the index of the row of the cel…
题目链接:uva 10831 - Gerg's Cake 题目大意:给定a和p.p为素数,问说是否存在x,使得x2≡a%p 解题思路:勒让德记号,推断ap−12≡1%p #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; ll pow_mod (ll a, ll n, ll mod) { ll ans = 1; while…
UVA 11825 - Hackers' Crackdown 状态压缩 dp 枚举子集 ACM 题目地址:option=com_onlinejudge&Itemid=8&page=show_problem&problem=2925" style="color:rgb(0,136,204); text-decoration:none">11825 - Hackers' Crackdown 题意:  有一个由编号0~n-1的n台计算机组成的网络,一共…
Problem D Morley's Theorem Input: Standard Input Output: Standard Output Morley's theorem states that that the lines trisecting the angles of an arbitrary plane triangle meet at the vertices of an equilateral triangle. For example in the figure below…
是典型的bfs,但是,这个问题的目的在于读取条件的困难,而不是简单地推断,需要找到一种方法来读取条件.还需要想办法去推断每一点不能满足条件,继续往下走. #include<cstdio> #include<cstring> #include<string> #include<queue> #include<iostream> #include<algorithm> using namespace std; struct note {…
Andy, 8, has a dream - he wants to produce his very own dictionary. This is not an easy task for him, as the number of words that he knows is, well, not quite enough. Instead of thinking up all the words himself, he has a briliant idea. From his book…
称号:区区女性有父亲和母亲,区区无人机只有一个母亲,我问一个单纯的无人机第一n随着祖先的数量. 分析:递归.Fib序列. 状态定义:建立f(k)和m(k)分别用于第一k雌蜂和雄蜂的数量: 递推关系:f(k)= f(k-1)+ m(k-1)和 m(k)= f(k-1): 递推整理:f(k)= f(k-1)+ f(k-2):f(1) = 1:f(2)= 2: 说明:使用long long防止溢出. #include <algorithm> #include <iostream> #in…
出发dp,用在一些议题的操作非常~  给出s个课程.m个教师.n个求职者,教师必须招聘.然后招聘一些求职者,使得每一门课都至少有两个老师能教.问题就转换成了招聘哪些求职者使得花费最少.由于s范围小于8.则能够用二进制表示,用集合s1表示恰好有一个人教的课的集合,用集合s2表示有两个人教的课的集合,则每次状态转移即为选择这名求职者还是不选(教师必须选)详细看代码. d(i,s1,s2) = min{ d(i+1,s1',s2')+c[i],d(i+1,s1,s2)} 第一项表示聘用,第二项表示不聘…
称号:给你一个行长度的建设和高度,我们祈求最长的和下降的高度. 分析:dp,最大上升子. 说明:具有长度,不能直接优化队列单调. #include <iostream> #include <cstdlib> #include <cstdio> using namespace std; int h[2000],w[2000],u[2000],l[2000]; int main() { int T,n; while (~scanf("%d",&T…
Shoemaker's Problem Shoemaker has N jobs (orders from customers) which he must make. Shoemaker can work on only one job in each day. For each ith job, it is known the integer Ti (1<=Ti<=1000), the time in days it takes the shoemaker to finish the jo…
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题意:给你正视和側视图,求最多多少个,最少多少个 思路:贪心的思想.求最少的时候:由于能够想象着移动,尽量让两个视图的重叠.所以我们统计每一个视图不同高度的个数.然后计算.至于的话.就是每次拿正视图的高度去匹配側视求最大 #include <iostream> #include <cstring> #include <cstdio> #include <algorithm> using namespace std; const int MAXN = 1000…
一道非常easy想复杂的题,给出主视图和右视图,计算最少能用几个正方体组成相应的视图,以及最多还能加几块正方体. 求最多加入事实上就是求出最多的正方体数减去最少的,主要就是最少的不好求. 一開始各种模拟就是不正确,之后发现,仅仅须要统计两个视图的高度个数就能够了(简直了) 14390495 434 Matty's Blocks Accepted C++ 0.016 2014-10-21 11:35:11 #include<cstdio> #include<cstring> #inc…
R-CNN论文翻译 Rich feature hierarchies for accurate object detection and semantic segmentation 用于精确物体定位和语义分割的丰富特征层次结构 2017-11-29 摘要         过去几年,在权威数据集PASCAL上,物体检测的效果已经达到一个稳定水平.效果最好的方法是融合了多种图像低维特征和高维上下文环境的复杂结合系统.在这篇论文里,我们提出了一种简单并且可扩展的检测算法,可以将mAP在VOC2012最…
Rich feature hierarchies for accurate object detection and semantic segmentation Tech report (v5) primary首要的 primate原始的 homogeneous均匀的 deformable可变形的 在最近几年中,在PASCAL VOC数据集上测量的目标检测的性能已经趋于平稳.性能最好的方法是复杂的.可理解的系统,这些系统通常将多个底层图像特性与高层上下文结合起来.在这篇论文中,我们提出了一个简单…
R-CNN论文翻译 <Rich feature hierarchies for accurate object detection and semantic segmentation> 用于精确物体定位和语义分割的丰富特征层次结构 文章出处:https://www.cnblogs.com/pengsky2016/. 摘要:         过去几年,在权威数据集PASCAL上,物体检测的效果已经达到一个稳定水平.效果最好的方法是融合了多种图像低维特征和高维上下文环境的复杂结合系统.在这篇论文里…
https://vjudge.net/contest/68264#problem/R The Sultan of Nubia has no children, so she has decided that the country will be split into up to k separate parts on her death and each part will be inherited by whoever performs best at some test. It is po…
the squares thus selected sum to a number at least as high as one already chosen by the Sultan. (For those unfamiliar with the rules of chess, this implies that each row and column of the board contains exactly one queen, and each diagonal contains n…
题目链接:Uva 167 思路分析:八皇后问题,采用回溯法解决问题. 代码如下: #include <iostream> #include <string.h> using namespace std; ; int A[MAX_N]; int M[MAX_N][MAX_N]; ; int is_safe( int row, int col ) { ; i < row; ++i ) { if ( A[i] == col ) return false; if ( A[i] + i…
The Sultan's Successors Description The Sultan of Nubia has no children, so she has decided that the country will be split into up to k separate parts on her death and each part will be inherited by whoever performs best at some test. It is possible…
偶数时,中位数之间的数都是能够的(包含中位数) 奇数时,一定是中位数 推导请找初中老师 #include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<algorithm> using namespace std; int box[1000000]; int main() { //freopen("in","r"…
UVA 12436 - Rip Van Winkle's Code option=com_onlinejudge&Itemid=8&page=show_problem&category=&problem=3867&mosmsg=Submission+received+with+ID+14331401" target="_blank" style="">题目链接 题意:区间改动一个加入等差数列,一个把区间设为某个…
UVA 11888 - Abnormal 89's option=com_onlinejudge&Itemid=8&page=show_problem&category=524&problem=2988&mosmsg=Submission+received+with+ID+14075396" target="_blank" style="">题目链接 题意:给定一个字符串.推断类型.一共三种.两个回文拼接成的,…
UVA 1397 - The Teacher's Side of Math 题目链接 题意:给定一个x=a1/m+b1/n.求原方程组 思路:因为m*n最多20,全部最高项仅仅有20.然后能够把每一个此项拆分.之后得到n种不同无理数,每一项为0.就能够设系数为变元.构造方程进行高斯消元 一開始用longlong爆了.换成分数写法也爆了,又不想改高精度.最后是机智的用了double型过的,只是用double精度问题,所以高斯消元的姿势要正确,而且最后输出要注意-0的情况 代码: #include…