Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0. Example 1: Input: 22 Output: 2 Explanation: 22 in binary is 0b10110. In the…

给定一个正整数 N,找到并返回 N 的二进制表示中两个连续的 1 之间的最长距离. 如果没有两个连续的 1,返回 0 . 示例 1: 输入:22 输出:2 解释: 22 的二进制是 0b10110 . 在 22 的二进制表示中,有三个 1,组成两对连续的 1 . 第一对连续的 1 中,两个 1 之间的距离为 2 . 第二对连续的 1 中,两个 1 之间的距离为 1 . 答案取两个距离之中最大的,也就是 2 . 示例 2: 输入:5 输出:2 解释: 5 的二进制是 0b101 . 示例 3: 输…

中文标题[二进制空白] 英文描述 A binary gap within a positive integer N is any maximal sequence of consecutive zeros that is surrounded by ones at both ends in the binary representation of N. For example, number 9 has binary representation 1001 and contains a bina…

LeetCode & Binary Search 解题模版 In computer science, binary search, also known as half-interval search, logarithmic search, or binary chop, is a search algorithm that finds the position of a target value within a sorted array. 在计算机科学中,二分搜索(也称为半间隔搜索,对数搜…

LeetCode:Binary Tree Level Order Traversal Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree {3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its level ord…

LeetCode: Binary Tree Traversal 题目:树的先序和后序. 后序地址:https://oj.leetcode.com/problems/binary-tree-postorder-traversal/ 先序地址:https://oj.leetcode.com/problems/binary-tree-preorder-traversal/ 后序算法:利用栈的非递归算法.初始时,先从根节点一直往左走到底,并把相应的元素进栈:在循环里每次都取出栈顶元素,如果该栈顶元素的右…

Given a sorted (in ascending order) integer array nums of n elements and a target value, write a function to search target in nums. If target exists, then return its index, otherwise return -1. Example 1: Input: nums = [-1,0,3,5,9,12], target = 9 Out…

[067-Add Binary(二进制加法)] [LeetCode-面试算法经典-Java实现][全部题目文件夹索引] 原题 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100" 题目大意 给定两个二进制的字符串,返回它们的和,也是二进行制字符串. 解题思路 先将相应的两个二进制字符…

problem 868. Binary Gap solution1: class Solution { public: int binaryGap(int N) { ; vector<int> pos; ; ) { ==) pos.push_back(k); k++; N >>=;//errr... } ; i<pos.size(); ++i) { res = max(res, pos[i]-pos[i-]); } return res; } }; solution2: cl…

LeetCode Binary Search All In One Binary Search 二分查找算法 https://leetcode-cn.com/problems/binary-search/ https://leetcode-cn.com/problems/binary-search/solution/er-fen-cha-zhao-by-leetcode/ 复杂度分析 时间复杂度:\mathcal{O}(\log N)O(logN). 空间复杂度:\mathcal{O}(1)O(…