转载请注明出处:http://blog.csdn.net/u012860063?viewmode=contents 题目链接:http://poj.org/problem? id=2488 ----------------------------------------------------------------------------------------------------------------------------------------------------------…

A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 29226   Accepted: 10023 Description Background  The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey …

A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 28697   Accepted: 9822 Description Background  The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey  a…

POJ 2488 -- A Knight's Journey(骑士游历) 题意: 给出一个国际棋盘的大小,判断马能否不重复的走过所有格,并记录下其中按字典序排列的第一种路径. 经典的“骑士游历”问题 输入:第一行,整数n,接下来是n行,每一行为p和q,p为行数,q为列数,p用1...p编号,q用A...Q编号 马的走法:每步棋先横走或直走一格,然后再往外斜走一格;或者先斜走一格,最后再往外横走或竖走一格(即走"日"字).可以越子,没有中国象棋中的"蹩马腿"限制. 解…

题目:http://poj.org/problem?id=2488 题意: 给出一个国际棋盘的大小,判断马能否不重复的走过所有格,并记录下其中按字典序排列的第一种路径. #include <iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<stack> #include<queue> #include<iomanip> #incl…

A Knight's Journey Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 31702   Accepted: 10813 Description Background  The knight is getting bored of seeing the same black and white squares again and again and has decided to make a journey …

A Knight's Journey Time Limit: 1000MSMemory Limit: 65536K Total Submissions: 34633Accepted: 11815 Description BackgroundThe knight is getting bored of seeing the same black and white squares again and again and has decided to make a journeyaround the…

A Knight's Journey Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 66   Accepted Submission(s) : 27 Problem Description Background The knight is getting bored of seeing the same black and white…

题目链接:http://poj.org/problem?id=2488 题意: 在国际象棋的题盘上有一个骑士,骑士只能走“日”,即站在某一个位置,它可以往周围八个满足条件的格子上跳跃,现在给你一个p * q的矩形格子,让你找一个跳跃顺序(起点自选),使得这个顺序恰好经过矩阵的每一个格子,且每一个格子仅经过一次,即找一个符合跳跃条件的序列,遍历整个矩形格子.如果有多个,那么就输出字典序最小的. 思路: 貌似可以利用哈密顿通路来解决,但是感觉有点太麻烦,没怎么细想,感觉还是回溯法比较好.首先题目要求…

题目地址:http://poj.org/problem?id=2488 Sample Input 3 1 1 2 3 4 3 Sample Output Scenario #1: A1 Scenario #2: impossible Scenario #3: A1B3C1A2B4C2A3B1C3A4B2C4 题目:给你一个p*q的棋盘,规则布局参考上图.列用字母表示,行用数字表示.这样一个左上角的节点就是(A,1).骑士的棋子走日字形状,可以从任意节点出发,终点也是任意的.问你能不能遍历所有的位…