Hat's Words Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9574    Accepted Submission(s): 3421 Problem Description A hat's word is a word in the dictionary that is the concatenation of exactl…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1247 Problem DescriptionA hat’s word is a word in the dictionary that is the concatenation of exactly two other words in the dictionary.You are to find all the hat’s words in a dictionary. InputStandard…

Problem Description A hat's word is a word in the dictionary that is the concatenation of exactly two other words in the dictionary. You are to find all the hat's words in a dictionary.   Input Standard input consists of a number of lowercase words,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1247 思路分析:题目要求找出在输入字符串中的满足要求(该字符串由输入的字符串中的两个字符串拼接而成)的字符串. 对于长度为LEN的字符串,其可能由LEN种可能的拼接可能:现在问题转化为查找能够拼接成该字符串的可能的两个字符串是否都在 输入的字符串中,使用字典树可以实现快速的字符串查找,算法复杂度为O(N*M),N为输入字符串的个数,M为字符串长度. 代码如下: #include <cstdio>…

Hat’s Words Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7282    Accepted Submission(s): 2639 Problem Description A hat’s word is a word in the dictionary that is the concatenation of exactly…

题意:给一个字符串集,要你给出n个字符串s,使s能被所给字符串集中的两个相加所得(ahat=a+hat) 思路:简单字典树题,注意查询的时候要判断所指next是否为NULL,否则会RE非法访问. 代价: #include<cstdio> #include<cstring> #include<cstdlib> #include<queue> #include<cmath> #include<string> #include<sta…

分析:一開始是用递归做的,没做出来.于是就换了如今的数组.即,把每个输入的字符串都存入二维数组中,然后创建字典树.输入和创建完成后,開始查找. 事实上一開始就读错题目了,题目要求字符串是由其它两个输入的字符串组成的前后缀,自己根本没有推断前缀是否满足.就直接推断后缀,一直想不通自己哪里错了,非常羞愧,水平还是不行. 查找分为前缀查找和后缀查找.事实上两个函数基本差点儿相同的.以下放代码. #include <cstdio> #include <cstring> #include &…

Hat’s Words Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16970    Accepted Submission(s): 6098 Problem Description A hat’s word is a word in the dictionary that is the concatenation of exactl…

个人心得:通过这道题,对于树的运用又加深了一点,字典树有着他独特的特点,那个指针的一直转换着实让我好生想半天, 不得不佩服这些发明算法人的大脑. 这题的解决方法还是从网上找到的,还好算法是自己实现得,没错!组合体只要进行分割再暴力搜索就好了, 步骤就是根据得到的字符串建立字典树,然后一一找寻时,一次拆开,只要俩边都满足在字典树里面找的到就是我们所要找的了. 关于字典树的建立的话,因为他是不知道子树的,所以只要判断出来不存在子树就malloc一个就好了, 注意指针的指向和递归的奥妙,很多更新都是在…

题目链接:pid=1247" target="_blank">http://acm.hdu.edu.cn/showproblem.php? pid=1247 Problem Description A hat's word is a word in the dictionary that is the concatenation of exactly two other words in the dictionary. You are to find all the h…