Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters.…

哈希表可以用ASCII码数组来实现,可以更快 public boolean isIsomorphic(String s, String t) { /* 思路是记录下每个字符出现的位置,当有重复时,检查另外一个map是不是也是对应位置重复 */ if (s.length()!=t.length()) { return false; } Map<Character,Integer> map1 = new HashMap<>(); Map<Character,Integer>…

Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters.…

给定两个字符串 s 和 t,判断它们是否是同构的.如果 s 中的字符可以被替换最终变成 t ,则两个字符串是同构的.所有出现的字符都必须用另一个字符替换,同时保留字符的顺序.两个字符不能映射到同一个字符上,但字符可以映射自己本身.例如,给定 "egg", "add", 返回 true.给定 "foo", "bar", 返回 false.给定 "paper", "title", 返回 tr…

Isomorphic Strings Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the or…

翻译 给定两个字符串s和t,决定它们是否是同构的. 假设s中的元素被替换能够得到t,那么称这两个字符串是同构的. 在用一个字符串的元素替换还有一个字符串的元素的过程中.所有字符的顺序必须保留. 没有两个字符能够被映射到同样的字符,但字符能够映射到该字符本身. 比如, 给定"egg","add",返回真. 给定"foo"."bar",返回假. 给定"paper","title",返回真.…

Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters.…

判断两个字符串是否同构 hs,ht就是每个字符出现的顺序 "egg" 与"add"的数字都是122 "foo"是122, 而"bar"是123 class Solution { public: bool isIsomorphic(string s, string t) { ] = {}; ] = {}; if (s.size() != t.size()) return false; ; ;i<s.size(); ++i)…

题意:如果两个字符串是对称的,就返回true.对称就是将串1中的同一字符都一起换掉,可以换成同串2一样的. 思路:ASCII码表哈希就行了.需要扫3次字符串,共3*n的计算量.复杂度O(n).从串左开始扫,若字符没有出现过,则赋予其一个特定编号,在哈希表中记录,并将该字符改成编号.对串2同样处理.其实扫2次就行了,但是为了短码. class Solution { public: void cal(string &s) { ]={}, cnt=; ; i<s.size(); i++) { if…

Problem: Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of cha…