Cow Bowling DescriptionThe cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard bowling-pin-like triangle like this: 7 3 8 8 1 0 2 7 …
Cow Bowling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 19173 Accepted: 12734 Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard…
Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard bowling-pin-like triangle like this: 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5 Then the other cows traverse…
描述 http://poj.org/problem?id=3176 给出一个三角形,每个点可以走到它下面两个点,将所有经过的点的值加起来,问最大的和是多少. Cow Bowling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 16826 Accepted: 11220 Description The cows don't use actual bowling balls when they go bowling.…
Cow Bowling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 13016 Accepted: 8598 Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard…
Cow Bowling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 15585 Accepted: 10363 Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard bow…
免费馅饼 Problem Description 都说天上不会掉馅饼,但有一天gameboy正走在回家的小径上,忽然天上掉下大把大把的馅饼.说来gameboy的人品实在是太好了,这馅饼别处都不掉,就掉落在他身旁的10米范围内.馅饼如果掉在了地上当然就不能吃了,所以gameboy马上卸下身上的背包去接.但由于小径两侧都不能站人,所以他只能在小径上接.由于gameboy平时老呆在房间里玩游戏,虽然在游戏中是个身手敏捷的高手,但在现实中运动神经特别迟钝,每秒种只有在移动不超过一米的范围内接住坠落的馅饼…
Cow Bowling Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 13464 Accepted: 8897 Description The cows don't use actual bowling balls when they go bowling. They each take a number (in the range 0..99), though, and line up in a standard…
题目大意:给定一个数字三角形,求从 (1,1) 走到最后一行的路径和对 100 取余数的最大值. 题解:由于最优解涉及到取余数的操作,因此按照原先的状态设计并不符合最优子结构性质,即:两个最大数相加取模并不能得到一个最优解.因此将其转化为可行性问题,即:再开一个维度记录下每个位置可能的模值,最后取第 N 行最大的一个就是答案. 代码如下 #include <bits/stdc++.h> using namespace std; const int maxn=30; int n,ans,mp[m…
